Question

..please help... 2log(4)3x+log(4)5x=log(4)225

Answer 1

so they are all log base 4 so rewriting the equation using log laws you get

\[\log_{4}(3x)^2 + \log_{4}(5x) = \log_{4}(225)\]

addition in logs means multiplication

\[\log_{4}(9x^2 \times 5x) = \log_{4}(225)\]

which becomes

\[\log_{4}(45x^3) = \log_{4}(225)\]

since they are the same base you just need to solve

\[45x^3 = 225\]

Answer 2

hope it helps

Answer 3

11 x Log[4] = 225 Log[4]