Question

need help with parabola equation please
One of the x-intercepts of the parabola represented by the equation
y = 3x^2 + 6x − 10 is approximately (1.08, 0).
The other x-intercept of the parabola is approximately ?
need to round to nearest hundred

Answer 1

3x^2+6x-10=0
I thought y was -10 but Im so confused. can anyone please help me?

Answer 2

hi

Answer 3

this function will not factor so you can use either completing the square or the quadratic root formula to find the roots

Answer 4

Hi

Answer 5

im not sure how to do that can you show me?

Answer 6

0=3x^2+6x-10

Answer 7

or you could also use the identities
A + B = -b/a

where A and B are the 2 roots and a and b are the coefficients in the general form

ax^2 + bx + c = 0

Have you done that in class yet?

Answer 8

yes it looks familar

Answer 9

3,6,-10

Answer 10

is it quadratic formula

Answer 11

knowing one root to can put A = 1.08 into the identity so
1.08 + B = -6/3 = -2
B = -3.08

Answer 12

3.08 would be x

Answer 13

and 0

Answer 14

No the quadratic formula i referred to was for working out the roots

x = [-b +/- sqrt(b^2 - 4ac)] / 2a

Answer 15

the x intercept would be (-3.08,0)

Answer 16

thank you

Answer 17

what comes after the -b+

Answer 18

that doesn't look right to me

Answer 19

yw

in the textbooks the identity for sum of the roots are usually written as the greek letters

alpha + beta = -b/a

Answer 20

\[\alpha +\beta \]

Answer 21

oh yes I've seen that

Answer 22

thanks again

Answer 23

yw