Can someone help me here: I'll medal and Thanks!
1. A 2. C. 3. B 4. not sure
@Michele_Laino
I think that we have an exponential growth
well excuse me, but i didnt realize they werent the same thing :(
I didn't see your data until now, sorry. At first sight I think that we have an exponential growth which can be modeled with the function below: \[\huge y = A \cdot {B^x}\] here we have to check the linear correlation between the subsequent variables: \(\log_{10} y\) and \(x\). If we take the \(logarithm\) of both sides, we can write this: \[\huge {\log _{10}}y = {\log _{10}}A + \left( {{{\log }_{10}}B} \right)x\] which is a linear relation between \( \log_{10}y\) and \(x\)
of course, here \(y\) is the number of fish, and \(x\) is the number of months
please in order to check my conjecture, try to draw the scatter plot using the data you provided
but you wouldn't need to would you, it on the chart provided
it shows larger amounts that are being various
ok! Then we can continue under the hypothesis of an exponential growth, so we have to compute, using an analytical linear fit, both constants \(\log_{10} A\) and \(\log_{10} B\), and then the values \(A\) and \(B\)
maybe my deciamls are off
why 2. D ?
my decimal was off never mind
sincerely I was expecting for a number greater than \(4,738\) as option
please try to apply the formulas for linear fit to my model above and then compute the two constants \(A\) and \(B\), after that, you are able to compute the number of fishes at fifth month, by direct substitution
ok so would it be 3, and does it have to be rounded
its not 4.5
why is it 3 ?
what is your reasoning, please?
i looked at goolge and it seemed it was correct
what is the link?
I meant the web-link you looked
there is not explanation there!
hm i see
Please, I solve your question using my reasoning and I will explain my solution tomorrow, since it involves a quite long computation
hm can we skip it then? how is the next one
I don't think that we are able to answer the subsequent questions, if we have not computed both constants \(A,\,B\) above
ok
ok! :)
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