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Mathematics 16 Online
OpenStudy (calculusxy):

Help in completing the square!

OpenStudy (calculusxy):

\[\large 2v^2 -20v - 7 = 7\]

OpenStudy (calculusxy):

@TheSmartOne

OpenStudy (anonymous):

\[v=5\pm4\sqrt{2}\]

TheSmartOne (thesmartone):

\(\sf\large a^2 -2ab + b^2 = (a-b)^2\) So we have a = 2 and 2ab = 20 so solve for b 2(2)b = 20 b = >

TheSmartOne (thesmartone):

b = ? *

OpenStudy (calculusxy):

\[2v^2 - 20v - 14 = 0\] divided everything by 2 \(v^2 - 10v - 7 = 0\) \(v^2 - 10v + (-10/2) = 7 + (-10/2)\) \(v^2 - 10v - 5 = 7 - 5\) \(\sqrt{v^2 - 10v - 5} = \sqrt{2}\) I know that i will be getting a very weird answer from the answer key.

OpenStudy (calculusxy):

is there anything that i am doing wrong?

TheSmartOne (thesmartone):

mhmm

TheSmartOne (thesmartone):

it should be (-10/2)^2

TheSmartOne (thesmartone):

because we have to add b^2 on both sides so we could simplify it :)

OpenStudy (calculusxy):

but for a previous question, i used the same thing that i am doing now and it matched with the answer key.

TheSmartOne (thesmartone):

but this time it isn't matching the answer key? o_0

OpenStudy (pawanyadav):

Co incidence ,or you match it wrong, it should be square of -5

OpenStudy (calculusxy):

okay i understand what you're saying. for the last one it was \((2/2)^2 = 1^2 = 1\) that's why i didn't understand that :)

TheSmartOne (thesmartone):

great :)

OpenStudy (calculusxy):

thanks!

TheSmartOne (thesmartone):

wait a second

OpenStudy (calculusxy):

ok

TheSmartOne (thesmartone):

nevermind, you got it correct :)

OpenStudy (calculusxy):

hold on a moment

OpenStudy (calculusxy):

so i did: \(v^2 - 10v + 25 = 7 + 25\) \(v^2 - 10v + 25 = 32\) \(32\) is not a perfect square but the answer key has whole numbers

OpenStudy (calculusxy):

@TheSmartOne

TheSmartOne (thesmartone):

so solving that we get \(\sf\Large v - 5 = \pm\sqrt{32}\) \(\sf \Large v = 5 \pm \sqrt{32}\) \(\sf\Large v = 5\pm 4\sqrt{2}\) what does the answer key say the answer is?

OpenStudy (calculusxy):

2v^2 - 12v - 7 = 7 {7,-1} <--- answer

OpenStudy (calculusxy):

do you know my mistake?

TheSmartOne (thesmartone):

maybe we shouldn't have simplified

TheSmartOne (thesmartone):

not sure really mhmm :/

OpenStudy (calculusxy):

what about this problem \(6v^2 - 12v - 84 = 6\)

TheSmartOne (thesmartone):

WAIT

TheSmartOne (thesmartone):

\(\color{blue}{\text{Originally Posted by}}\) @calculusxy 2v^2 - 12v - 7 = 7 {7,-1} <--- answer \(\color{blue}{\text{End of Quote}}\) we have -12v here not -20v as you posted

OpenStudy (calculusxy):

oh wow!

TheSmartOne (thesmartone):

:)

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