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What is the directrix of the parabola defined by 14(y+3)=(x−2)2?
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HI!!
you need the vertex first do you know it?q
just asking if not, say so and i will tell you
no
ok it looks like \[4p(y-k)=(x-h)^2\] has center \((h,k)\)so your center is \((2,-3)\)
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is that the directrix
no that is the vertex, we need that first so we can find the directrix
okay
\[4p=14\] so \[p=\frac{14}{4}=\frac{7}{2}\] that means the directrix is \(\frac{7}{2}\) units down from \((2,-3)\)
so then it would just be 7/2
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no, 7/2 units below \((2,-3)\) that is why we needed the vertex first q
\[-3-\frac{77}{2}=-\frac{13}{2}\] the directrix is \[y=-\frac{13}{2}\]
oh and the directix is a horizontal line, not a number so it is the equation \[y=-\frac{13}{2}\]
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