Question

help

Answer 1

solve:
64b^2+49=0

Answer 2

64=8*8
49=7*7

so basicly this is the diffrence of complex roots

Answer 3

difference of squares of complex roots

Answer 4

Hint:

\(\sf\Huge a^2 + b^2 = (a+bi)(a-bi)\)

Answer 5

yeah

Answer 6

:)

Answer 7

so A

Answer 8

yeah

Answer 9

nope

Answer 10

thanks

Answer 11

you lost the `i`

Answer 12

wait

Answer 13

it's not A

Answer 14

HHAHA i did lost it too omg

Answer 15

you forgot about i

Answer 16

so D

Answer 17

Hint:

\(\sf\Huge a^2 + b^2 = (a+b\color{red}{i})(a-b\color{red}{i})\)

Answer 18

yes

Answer 19

yup :)

Answer 20

D is correct

Answer 21

Good job @AlexandervonHumboldt2 and @itsmichelle29 :)

Answer 22

y the i

Answer 23

n.m. i get it lol

Answer 24

you see the a^2 + b^2 formula is not the same as a^2 - b^2 formula

a^2 - b^2 = (a+b)(a-b)

Answer 25

Answer choice A is based off of the a^2 - b^2 formula

not the a^2 + b^2 formula

Answer 26

you cannot factor a^2-b^2 using rational values

Answer 27

wioops

Answer 28

i meant a^2+b^2

Answer 29

you have to use complex numbers

Answer 30

Let's cross multiply

\(\sf\LARGE (a+b\color{red}{i})(a-b\color{red}{i})=a^2+abi -abi -(bi)^2\\\\\LARGE a^2 - (bi)^2 = a^2 -(b^2)(i^2) = a^2 - (b^2)(-1) = \\\\\Large\boxed{a^2 + b^2} \)

Answer 31

do you understand? :)