Question

1.Find the slope of the linear line between the points (-4, 5) and (6, 1).

2.Find the slope of the linear line between the points (10, -4) and (4, -4).

Answer 1

\[\large\rm \frac{ y_2 -y_1 }{ x_2-x_1 }\] formula to find slope between two points \[\rm (x_1,y_1)(x_2,y_2)\]

Answer 2

\[\rm \large \rm (\color{Red}{x_1},\color{blue}{y_1})(\color{red}{x_2},\color{blue}{y_2} )\]\[\rm \large \rm (\color{Red}{-4},\color{blue}{5})(\color{red}{6},\color{blue}{1} )\]
plugin x's and y's values into the formula then simplify

Answer 3

x=-10 and y=4??? help me :( @Nnesha

Answer 4

`1.Find the slope of the linear line between the points (-4, 5) and (6, 1).`
first question

Answer 5

(x,y) ordered pair where first number represent x-coordinate and 2nd one y-coordinate
so (-4,5) where x=-4
and y=5

Answer 6

so
x=-4 - x=6
y=5 - y=1

Answer 7

yes correct
so now plug that into the formula
(x_1,y_1)(x_2,y_2)
x_1 means first x
y_2 means 2nd y

Answer 8

but remember y values should be at the numerator

Answer 9

x=-4 - x=6
y=5 - y=1
equals
x=2??
y=4??

Answer 10

hmm
if x=-4 and x=6
then what would be -4-6 = ?

Answer 11

\[\large\rm \frac{ y_2 -y_1 }{ x_2-x_1 }\] this is the formula
plugin x =-4 and x=6
\[\large\rm \frac{ y_2 -y_1 }{ 6-(-4) }\] same with y values

Answer 12

-4-6=-10

6-(-4)=10

Answer 13

yes correct so so what would be the final answer ?\[\frac{ 1-5 }{ 6-(-4) } =\frac{-4}{10}\]
you will get the same answer doens't matter if you write y_1 first or y_2

Answer 14

now just reduce the fraction

Answer 15

-4/10=-0.4

Answer 16

slope = rise over run so keep that in fraction form
divide top and bottom of the fraction by 2

Answer 17

-4/10=2/5
am I correct?

Answer 18

ye but it should be negative bec negative divide by positive = negative

Answer 19

sorry I had to fix it and I guess I may have deleted the negative sign so the answer is -2/5

Answer 20

correct.

Answer 21

thank you can you tell me if im correct on #2?

Answer 22

sure try it first show ur work i'll check :=))

Answer 23

x=10,4
y=-4,-4

Answer 24

ye those are x and y values not plug that into the formula

Answer 25

now**

Answer 26

10-4=6
-4(-4)=16
6/16=3/8
am I correct the answer is 3/8???

Answer 27

remember the formula is in other words \[\rm \frac{ change~ in~y's }{ change ~ in~x's }\]

Answer 28

subtract y values in the numerator
and subtract x's values in the denomiantor
so we should subtract them not multiply

Answer 29

-4(-4)=16
10-4=6
16/6=8/3???

Answer 30

don't do it serrate use the formula again we are not multiplying y values we should subtract them

Answer 31

\[\large\rm \frac{ y_2 -y_1 }{ x_2-x_1 }\]
write like this in fraction form

Answer 32

separate **

Answer 33

-4(-4)=16
4-10=-6
16/-6???

Answer 34

like i said before we are NOT multiplying

Answer 35

subtract y values
not multiply 4(-4) isn't correct

Answer 36

it should be 2 negatives -4-4=-8

Answer 37

no that's the reason i'm saying use the formula

Answer 38

there is a negative sign in the formula
here \[\large\rm \frac{ y_2 -y_1 }{ x_2-x_1 }\]
substitute y_2 for -4 and y_1 for -4

Answer 39

as in y_1 you mean 10 and y_2 you mean 4

Answer 40

10 and 4 are x-coordinate not y -coordinate
x_1 =10
x_2=4
y_1=-4
y_2=-4

Answer 41

substitute x's and y's for the values