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Mathematics 6 Online
OpenStudy (anonymous):

https://static.k12.com/eli/bb/652/2_35734/2_32034_4_35738/d3e7c4e01d5bca685bb02127c0a96df83caabc28/media/76a1576e25dd19de21e9b0e76f94b07b29cd839a/mathml_76dca2a1916186e0ebc1bdfb34e65a9c9910fdd7_1.gif Which of the following shows the correct steps for solving

OpenStudy (anonymous):

@thesmartone

TheSmartOne (thesmartone):

Hi! Welcome to OpenStudy! :D @cruznatalie150

TheSmartOne (thesmartone):

First we need to make the same bases.

TheSmartOne (thesmartone):

Let's make both sides of the equation have a base of 3. Hint: Make the right side have a base of 3. Remember this formula: \(\sf\Large (a^b)^c = a^{bc}\) Also, to solve for the variables in your question we will use this formula: \(\sf\Large a^b = a^c \bf{\color{red}{=>}}\Large b = c\)

TheSmartOne (thesmartone):

Another hint: 9 = 3^2

OpenStudy (anonymous):

@thesmartone thanks I barely saw your message

OpenStudy (anonymous):

So you multiply by 3

OpenStudy (anonymous):

@mw3030 how do you know

TheSmartOne (thesmartone):

no, you don't multiply by 3.

TheSmartOne (thesmartone):

ok, let me show you an example :)

TheSmartOne (thesmartone):

\(\sf\Large 4^{x+4} = (4)^{x+4} = (2^2) ^{x+4} = 2^{2(x+4)} =2^{2x+8}\)

TheSmartOne (thesmartone):

but you need to do that for your question :)

OpenStudy (anonymous):

Oh ok it's because this question I have never heard or done anything like this before and it was so confusing and it was a oh weird question and I don't know the rules or the formulas or how to solve it that's why I needed your help not really cause of the answer but I just gave you the answer choices because some people be like I want you to wake you know what I mean because you are

OpenStudy (anonymous):

@thesmartone

TheSmartOne (thesmartone):

uhhhh ok, but can you do what I did in the example above?

OpenStudy (anonymous):

yeah i got it and i did solve it was x

OpenStudy (anonymous):

=-1

TheSmartOne (thesmartone):

correct :)

OpenStudy (anonymous):

thankssorry for the misunderstanding@thesmartone

TheSmartOne (thesmartone):

no problem :)

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