Question

A bucket is raised from a well by means of a ropw which is wound around a wheel of diameter 77cm.Given that the bucket ascends in 1 minute 28 seconds with a uniform speed of 1.1m/s , calc the number of revolutions the wheel makes in raising the bucket

pi = 22/7

Answer 1

@hba

Answer 2

Can you like visualize it using the draw tool

Answer 3

n = distance/2*pi*r

Answer 4

88*1.1 = 96.8

Answer 5

we need to convert cm to m

Answer 6

@rvc

Answer 7

first step
the distance \(d\) covered by the rope linked to the bucket, is:

\[\huge d = vt = 1.1 \cdot 88 = ...?\]

Answer 8

since 1 minute and 28 seconds are equal to \(88\) seconds

Answer 9

@AaronAndyson

Answer 10

96.8

Answer 11

@Michele_Laino

Answer 12

kya huha
kya nahi samjha?

Answer 13

pora question

Answer 14

math mera ok ok h

Answer 15

physics hai ye correct

Answer 16

but yeh circles area perimeter wala sums dimag khrb kardete hain

Answer 17

nahi nahi ji this has to do with circumference of a cirlce

Answer 18

haan circumference kya part nahi samjha?

Answer 19

smjha h par yeh revolution wala nhi

Answer 20

what do you mean by revolution?

Answer 21

read the question again @rvc

Answer 22

i know boy
will u answer my question :)

Answer 23

first we should write all the given data

Answer 24

n = ?
speed = 1.1 ms
time = 88s
pi = 22/7
circumference = 2*pi*r

Answer 25

diamter of wheel = 77 cm

Answer 26

thats .77 m ryt..??

Answer 27

revolution means one complete cycle
in a circle one revolution will be the circumference of the circle correct?

Answer 28

yes

Answer 29

so calculate it :)

Answer 30

we need the no of revolution not the circumference...

Answer 31

1cm = 0.01m

Answer 32

\(\rm N=2 \pi r\\~N=\pi \cdot~d\\~N~is~the~no~of~revolution\)

Answer 33

tsk tsk

Answer 34

tsk?

Answer 35

they have not askedthe circumference yaar

Answer 36

idk im confused

Answer 37

second step:
the length of the circumference of the wheel is:
\[\huge C = 2\pi r \simeq 6.28 \cdot 77 = ...?\]

Answer 38

oops.. I have made an error, here is the right formula:
\[\huge C = 2\pi r \simeq 6.28 \cdot \frac{{0.77}}{2} = ...?\]
please continue

Answer 39

2.14

Answer 40

I got: \(C=2.41\)

Answer 41

the requested number \(N\) is therefore:
\[\huge N = \frac{d}{C} = \frac{{96.8}}{{2.42}} = ...?\]

Answer 42

40.1

Answer 43

correct! \(N=40\)

Answer 44

0.77 m is the diameter so should we divide by 2 to get the radius..?

Answer 45

yes!

Answer 46

2r=d

Answer 47

that's right!! :) @rvc

Answer 48

since the formula has
2 pi r
u can club 2r as d
then it will be pi d