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OpenStudy (anonymous):
How do u come from this expression :-http://prntscr.com/96pjbx to this one:- http://prntscr.com/96pjju
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OpenStudy (dayakar):
(k+1) is common in two terms
OpenStudy (anonymous):
yah.. but I still didn't get.. about tht 1/2 remaining der... I am really feelin dizzy! pellet!
OpenStudy (dayakar):
(k+1) (k/2 +1) = (k+1) (k/2+2/2) [ 1= 2/2]
OpenStudy (dayakar):
\[(k+1) \frac{( k+2) }{ 2 }\]
OpenStudy (dayakar):
do u get it
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OpenStudy (anonymous):
kk
OpenStudy (anonymous):
lel.. dumb me! eheh
OpenStudy (anonymous):
tx!
OpenStudy (dayakar):
|dw:1448445002754:dw|
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