Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

How do u come from this expression :-http://prntscr.com/96pjbx to this one:- http://prntscr.com/96pjju

OpenStudy (dayakar):

(k+1) is common in two terms

OpenStudy (anonymous):

yah.. but I still didn't get.. about tht 1/2 remaining der... I am really feelin dizzy! pellet!

OpenStudy (dayakar):

(k+1) (k/2 +1) = (k+1) (k/2+2/2) [ 1= 2/2]

OpenStudy (dayakar):

\[(k+1) \frac{( k+2) }{ 2 }\]

OpenStudy (dayakar):

do u get it

OpenStudy (anonymous):

kk

OpenStudy (anonymous):

lel.. dumb me! eheh

OpenStudy (anonymous):

tx!

OpenStudy (dayakar):

|dw:1448445002754:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!