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Mathematics 12 Online
OpenStudy (anonymous):

please help

OpenStudy (anonymous):

OpenStudy (anonymous):

You need to find the length. So you can read the length on the graph for, Amber to Betsey, and from Betsey to Claire. What is the length?

OpenStudy (anonymous):

a - b= 8 units b - c= 7 units

OpenStudy (anonymous):

after this got time for another?

OpenStudy (anonymous):

Yea, so now you need to find the length from a to c. This is done by Pythagoras again. \[a^2+b^2=c^2\]

OpenStudy (anonymous):

c is the hypotenuses, while a and b is the legs

OpenStudy (anonymous):

Do you know how to find the length c now?

OpenStudy (anonymous):

\[a^2+b^2=c^2 <=> c=\sqrt{a^2+b^2}\]

OpenStudy (anonymous):

ok here is the other 2

OpenStudy (anonymous):

What answer did you get? How many blocks does Amber walk?

OpenStudy (anonymous):

10.63

OpenStudy (anonymous):

thats squqre root

OpenStudy (anonymous):

square

OpenStudy (anonymous):

113 is before square root

OpenStudy (anonymous):

Yes so you get \[c=10.63\] Now the answer is \[10.63+7=17.63\] Because she walks from A to C and from C to B :)

OpenStudy (anonymous):

Now in question 4. Here you have 2 legs again, so you should be able to calculate the hypotenuses right? - You just use the Pythagorean theorem

OpenStudy (anonymous):

oh i see thanks

OpenStudy (anonymous):

i got 250 do i square root them?

OpenStudy (anonymous):

or is that my answer

OpenStudy (anonymous):

\[c=sqrt(5^2+15^2)\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

So it is either \[c=sqrt(250)\] or if you want to find it in decimal it is around 15.8 or so. But you have an answer \[sqrt(250)\] So that would be it :)

OpenStudy (anonymous):

For the last question 5: "In mathematics, the Pythagorean theorem, also known as Pythagoras' theorem, is a relation in Euclidean geometry among the three sides of a right triangle." - Source: Wikipedia. So the key word here is "right triangle". You can ONLY use this Pythagorean theorem on a RIGHT triangle. So what triangle is right? If you look at the pictures?

OpenStudy (anonymous):

b? also i have to more and thats it do you have time

OpenStudy (anonymous):

That is correct

OpenStudy (anonymous):

Sure, I got a little bit of time

OpenStudy (anonymous):

there they are ive never head of what the triples are

OpenStudy (anonymous):

waity the 4.png is wrong

OpenStudy (anonymous):

this is the right one

OpenStudy (anonymous):

So lets look at question 5. You need to use the theorem again, but this time you have to "make your own" RIGHT triangle.

OpenStudy (anonymous):

OpenStudy (anonymous):

ok so its 6.40 ?

OpenStudy (anonymous):

Correct

OpenStudy (anonymous):

So about the last question, you have these Pythagorean tripes. They are special. Lets look at 3,4,5. You have 2 legs 3,4 and the hypotenuse 5. \[a^2+b^2=c^2 <=> c=sqrt(a^2+b^2)\] Now with this triangle you get: \[c=sqrt(3^2+4^2)=sqrt(25)=5\]

OpenStudy (anonymous):

They give this nice and whole positive number, as their hypotenuses.

OpenStudy (anonymous):

ok so is the last one 17 the 8 ,15 ,17

OpenStudy (anonymous):

I have to admit, I dont know exactly what the question wants you to do. But The smallest Pythagorean Triple is 3, 4 and 5. And yes 8,15,17 is also a pythagorean triple. \[c=sqrt(8^2+15^2)=sqrt(289)=17\]

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