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Mathematics 7 Online
OpenStudy (anonymous):

Could any1 explain me how \[(n+2)!\] is equal to \[(n+2)(n+1)n!\]?

OpenStudy (pawanyadav):

Like 5!=5(5-1)!=5(5-1)(5-2)!=5(4)(3!) You know n!=n(n-1)! So it is (n+2)!=(n+2)(n+2-1)! =(n+2)(n+1)! I similar way (n+1)!=(n+1)n! So (n+2)!=(n+2)(n+1)n!

OpenStudy (anonymous):

Thanks :)

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