The position of an object at time t is given by s(t) = -2 - 6t. Find the instantaneous velocity at t = 2 by finding the derivative.
Do you need to find \[s'(2)?\]
I have no idea what this question is asking me to do
This shows your problem
Hint, we know \(\Large\frac{ds}{dt} = v\) So if we find the derivative of the function, we will know the velocity at any given point So we merely take the derivative function and plug in t = 2, what do you get? *dont overthink it when you take the derivative*
Paraphrasing john: Differentiate s(t) = -2 - 6t with respect to time, t.
im so confused :/
@Abbs__ are you there? This question pertains to applications of the derivative, important for you to know. Given a function such as s(t), which here represents position (how far an object is from the origin), the derivative with respect to t can represent speed or the magnitude of velocity. Similarly, if you find the 2nd derivative of s(t) with respect to t, the result can represent the acceleration
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