Question

1) Write an equation in point-slope form for the line through the given point with the given slope.

(5, 2); m = 3


2) Write an equation in point-slope form for the line through the given point with the given slope.

(-10, -6); m = -5/8


3) Write y = (-3/4)x + 3 in standard form using integers.

Answer 1

For 1 and 2 use this
\[\huge y-y_1=m(x-x_1)\]
where
m=slope
(x1,y1)

Answer 2

2 - 2 = 3( 5 - 5)?

Answer 3

O_o
1)
x1=5
y1=2
m=3
plug them into the formula
y-y1=m(x-x1)

Answer 4

y - 2 = 3( x - 5)

Answer 5

perfect!
Do the same for #2

Answer 6

2)
x1 = -10
y1 = -6
m = -5/8

y - y1 = m(x - x1)
y - (-6) = -5/8(x - (-10)

Answer 7

perfect :D
BUT when we have 2 negative signs next to each other they become postitive :)
\[\huge~\rm~y +6 = -5/8(x +10) \]

Answer 8

Thanks!

Answer 9

=)
Ok i am not sure about #3 i havent done that in a while perhaps @Photon336 can explain that part?

Answer 10

okay

Answer 11

@Luigi0210

Answer 12

Do you know what standard form is?

Answer 13

yes

Answer 14

Basically, it wants you to put it in standard form without any fractions/decimals.

I'm assuming this is "Standard Form of A Linear Equation" so we use \(\large Ax+By=C \)
Where A cannot be negative and A&B shouldn't be 0, and A, B, and C are integers (:

Answer 15

So like 3x - 4y = 12?

Answer 16

Yup! Except that -4y should be a +4y (:

\(\large y=-\frac{3}{4}x+3 \)

\(\large \frac{3}{4} x +y=3 \)

\(\large 3x+4y=12 \)

Answer 17

Thank you so much!!!

Answer 18

No problem!

Answer 19

Good job bui!! :D