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Concentration in ppm question:
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If I have 0.1840 g of ferrous ammonium sulphate \[Fe(NH _{4})_{2}(SO _{4})_{2} \times 6 H _{2}O\] (mm=284.05 g/mol) and want to know what the concentration of ferrous ion how would I go about it?
Thank you in advance
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