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Mathematics 13 Online
OpenStudy (anonymous):

Find the missing lengths of the sides.

OpenStudy (anonymous):

where?

OpenStudy (anonymous):

OpenStudy (hitaro9):

Alright. Are you familiar with the notation with the small dashed lines?

OpenStudy (anonymous):

yes.

OpenStudy (hitaro9):

|dw:1448593879046:dw|

OpenStudy (hitaro9):

Like A = 6 there

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok then nvm lol

OpenStudy (hitaro9):

Oh okay then. So we know that whatever the answer will be, a and b will be the same. So we can immediately rule out b).

OpenStudy (anonymous):

XD, Tanks tho .fedorable.

OpenStudy (anonymous):

ok

OpenStudy (hitaro9):

Now, question, have you ever seen something called the "Pythagorean Theorem?"

OpenStudy (anonymous):

yes, a^2 + b^2 = c^2

OpenStudy (hitaro9):

Alright then. So do we know any of the values in that equation right now?

OpenStudy (anonymous):

Yes, I know that c = 12 sqrt(2)

OpenStudy (hitaro9):

Awesome. Now, we know that a = b right?

OpenStudy (anonymous):

right

OpenStudy (hitaro9):

So whenever we have an equals sign, we can substitute one for the other right? Like if x=y then if x=5 then y=5 right?

OpenStudy (caozeyuan):

the easier way to do is just do 12sqrt(2)/sqrt(2), becuase we know its a 45/45/90, which means the legs are 1/sqrt(2) of the longest side

OpenStudy (anonymous):

right @ Hitaro

OpenStudy (hitaro9):

So we can make this equation a^2 + b^2 = c^2 a^2 + b^2 = (12sqrt( 2 )) ^2 a^2 + a^2 = (12sqrt (2 )) ^2

OpenStudy (anonymous):

ok. That makes sense.

OpenStudy (hitaro9):

So is there any way we can simplify that?

OpenStudy (anonymous):

yes, u can add like variables.

OpenStudy (hitaro9):

Right. So that would be 2a^2 = 12(sqrt2)^2

OpenStudy (hitaro9):

Think you can take it from there?

OpenStudy (hitaro9):

\[2a^2 = (12\sqrt{2})^2\]

OpenStudy (anonymous):

I would have to get a by itself right... So, 2a^2 = 12(sqrt)2^2 2a^2 / 2 = 12(sqrt)2^2 / 2 a^2 = 6(sqrt)2... No, I don't get it... Im sorry. Could u pls walk me thru it.

OpenStudy (hitaro9):

I wrote the equation wrong in text form, that's my bad. the 12 is inside the square.

OpenStudy (hitaro9):

The correct equation is a couple replies up.

OpenStudy (anonymous):

Oh! I see it Tanks. Let me try again.

OpenStudy (anonymous):

2a^2 = (12sqrt2)^2 here is where i am confused, am I supposed to get rid of the square first or the 2 before the a, to get a^2 by itself?

OpenStudy (hitaro9):

Right. Right now its a bit difficult to simplify the left side because dividing by two doesn't work. So maybe we can simplify the right side. Can you simplify (12sqrt(2))^2 ?

OpenStudy (anonymous):

12sqrt(2) = 16.9 or 17.

OpenStudy (hitaro9):

Okay hold on. Can you solve (sqrt(2))^2 ?

OpenStudy (anonymous):

2

OpenStudy (hitaro9):

Alright awesome. How would you solve (2sqrt(2))^2?

OpenStudy (anonymous):

Sorry I am having a lot of lag on my end.

OpenStudy (hitaro9):

Yeah. Openstudy can be finicky. So, how might we go about solving (2sqrt(2))^2 ?

OpenStudy (anonymous):

Do u mean (12sqrt(2)^2?

OpenStudy (hitaro9):

Yes.

OpenStudy (hitaro9):

(my bad)

OpenStudy (anonymous):

k, 24.

OpenStudy (hitaro9):

Can you walk me through your steps to get that?

OpenStudy (anonymous):

I used the calculator. :( I am allowed to do that in my school. Unfortunatly I don't know how to get it.

OpenStudy (hitaro9):

\[2a^2 = (12\sqrt{2})^2\]

OpenStudy (hitaro9):

Okay. So, let's think this through. Squaring a number is multiplying it by itself. So we're trying to find 12sqrt(2) times 12sqrt(2)

OpenStudy (hitaro9):

But this is kinda awkward, because we don't have an intution on how to multiply these quite yet. So what I'm going to do, is ask you to subtitute z= sqrt(2). Can you solve 12z times 12z?

OpenStudy (anonymous):

144z

OpenStudy (hitaro9):

Hmm okay. Can you solve 3a times 3a ?

OpenStudy (anonymous):

9a^2

OpenStudy (hitaro9):

Perfect. So what is 12z times 12z again?

OpenStudy (anonymous):

144z^2

OpenStudy (hitaro9):

Awesome. Now, we substituted z for sqrt(2) right? so if z = sqrt(2) what is 144(z^2)?

OpenStudy (anonymous):

I think it is 144((sqrt(2)^2)

OpenStudy (hitaro9):

Right, so that's 144(2) right? So 2a^2 = 144(2)

OpenStudy (anonymous):

oh, right

OpenStudy (hitaro9):

So can you solve for a?

OpenStudy (anonymous):

Divide both sides by 2.

OpenStudy (anonymous):

?

OpenStudy (hitaro9):

Right

OpenStudy (hitaro9):

So, you good? Have you found a?

OpenStudy (anonymous):

Ok, so I would end up with a^2 = 144. Then I would end up w/ 12? Right!!

OpenStudy (hitaro9):

Yep! Awesome job. Hopefully all that muddying around with how to multiply square roots didn't take away from the concept. Could you solve this simpler problem? |dw:1448597486372:dw|

OpenStudy (anonymous):

The legs each = 16, right?

OpenStudy (hitaro9):

well let's remember the steps. What would the pythagorean theorem look like in this situation?

OpenStudy (anonymous):

oh, right sorry. 256

OpenStudy (anonymous):

Um one sec, a^2 + b^2 = 32^2 or 256

OpenStudy (hitaro9):

I'm realizing this problem isn't actually easier, I tried to set up one with simple numbers but I think I just made it more complicated.

OpenStudy (anonymous):

Im sorry... I thought I was starting to understand.

OpenStudy (hitaro9):

Either way, you let a =b because the two sides are congruent. so you end up with a^2 +a^2 = 256 2a^2 =256 a^2 = 128 a = sqrt(128)

OpenStudy (hitaro9):

No no no, what you said was perfectly right

OpenStudy (anonymous):

oh! Ok great!!

OpenStudy (hitaro9):

Like, imagine I was trying to explain division, so I tried to pick and example like 8 divided by 2 But by accident I actually did 1596/1405

OpenStudy (hitaro9):

Anyways, does each step make sense? feel free to let me know if it doesn't.

OpenStudy (anonymous):

Yes! Thank you so much!! You should be a qualified helper!!

OpenStudy (hitaro9):

Awesome, feel free to let me know if you have any more questions.

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