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Algebra
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2x+3y=1200 as a y intercept form
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Hi! Welcome to openstudy!! :D To start with we need to subtract both sides by 2x \[\huge~\rm~\bf2x-2x+3y=1200 -2x\]
@Collin2000
when you do that you are left with \[\huge~\rm~\bf 3y=1200−2x\] \[\huge~\rm~\bf 3y=-2x+1200\] Divide everything by 3 because we are solving for "Y" \[\huge~\rm~\bf 3y/3=-2x/3+1200/3\] From here you will get the slope intercept form :)
Hint: When u want to find y-intercept\[\huge~\rm~\bf x=0\]
Substitute\[\huge~\rm~\bf x=0\] into the equation\[\huge~\rm~\bf 2x+3y=1200\]
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\[\huge~\rm~\bf 2(0)+3y=1200\]
\[\huge~\rm~\bf 3y=1200\]Then divide both sides by 3
\[\huge~\rm~\bf \frac{ 3y }{ 3 }=\frac{ 1200 }{ 3 }\]
\[\huge~\rm~\bf y=?\]solve it @Collin2000
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