Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -36 and 2304, respectively.
the nth term of a G S is given by a1 r^(n-1) where a1 = first term and r = common difference
so the second term = a1 r and 5th term = a1 r^4 so we have a1 r^4 2301 ---- = ---- a1 r -36
Can you find the value of r?
Basically correct. Might be clearer to draw the formula for arith. sequence, or to use Equation to make it fancy-clear.\[a _{n=}a _{0}*r ^{(n-1)}\]
a sub 0 is the first value of the sequence. r is the common factor.
When you come back online, please let the rest of us know what further info you may need to get started.
i got it guys
thank you
i have another question
Find the sum of the arithmetic sequence. -4, -1, 2, 5, 8, 11, 14 how do you do that?
There's a simple formula for that. If s is the sum of the sequence, a is the first term, n is the number of terms, and d is the difference between terms, s = a + (n - 1)*d
You've typed in a sequence. What are the values of a, n and d here?
um
-4, 7, and i dont know the last one
How far apart are -4 and -1? How far apart are 5 and 8? This should tell you the value of "d."
three
Right. So, a=-4, n=7 and d=3. Can you now find the sum of these 7 terms?
You could check your result by actually adding them up.
waitso i just plug it in
i got 14 ??????
nvmgot it, 35 right
35 is correct
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