Question

Torque problem pls read inside help

Answer 1

Have you tried using \(\rm {\tau = r\times F}\)

?

Answer 2

I got this

Answer 3

l i j k l
l 2 -3 2 l
l Fx 7 -6 l
= 4i + (2Fx + 12)j + ( 14 + 3Fx)k

Answer 4

τ = 4 i + 12 j + 14k = 4i + (2Fx + 12)j + ( 14 + 3Fx)k

Answer 5

okay what to do I don't know

Answer 6

Equate the corresponding components
\[\vec \tau.\hat i=(\vec r \times \vec F). \hat i\]

Answer 7

\[\vec \tau. \hat j=(\vec r \times \vec F).\hat j\]\[\vec t .\hat k=(\vec r \times \vec F).\hat k\]

Answer 8

still confuse I mean.. can you guide my equation to the answer.. I already done something

Answer 9

I think I've done the cross product but the problem is idk what to do after

Answer 10

τ = 4 i + 12 j + 14k = 4i + (2Fx + 12)j + ( 14 + 3Fx)k

Answer 11

\[\vec \tau=4 \hat i+12 \hat j+14\hat k\]
and
\[\vec \tau=4 \hat i+(2F_{x}+12)\hat j+(14+3F_{x}\hat k)\]
Since these are equal vectors, their x y and z components should be equal
\[4=4\]
\[2F_{x}+12=12\]
\[14+3F_{x}=14\]

Answer 12

thanks got it

Answer 13

Yeap thankyou guys will close the problem now!

Answer 14

yeah that looks good !