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Mathematics 20 Online
OpenStudy (kittiwitti1):

A. If a projectile (such as a bullet) is fired into the air with an initial velocity v at an angle of elevation θ (see the figure below), then the height h of the projectile at time t is given by \[h = −16t^{2} + vt \sin{θ}\]http://prntscr.com/98aa01 *** B. Use your graphing calculator to find the solutions to the following equation for 0 ≤ θ < 360° by graphing the function represented by the left side of the equation and then finding its zeros. Make sure your calculator is set to degree mode. (Round your answers to one decimal place. Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.) • http://prntscr.com/98a0gv • http://prntscr.com/98a0in • http://prntscr.com/98a0px If any one of these is solved for me I should be able to get the rest, thanks in advance--

OpenStudy (kittiwitti1):

@ganeshie8

ganeshie8 (ganeshie8):

how are you stuck on part A ?

ganeshie8 (ganeshie8):

you just need to plugin the given values of \(v\) and \(\theta\) right ?

OpenStudy (kittiwitti1):

I did and then got lost

OpenStudy (kittiwitti1):

it's 6 am and I haven't slept haha sorry -- ^^;

ganeshie8 (ganeshie8):

for part A you should get \[h = -16t^2 + 950t\]

OpenStudy (kittiwitti1):

ok

OpenStudy (kittiwitti1):

950???

ganeshie8 (ganeshie8):

sin(30) = 1/2 so, 1900tsin(30) = 1900t*1/2 = 950t

OpenStudy (kittiwitti1):

ah, so that's the equation...? *brain processing issues* o-0

ganeshie8 (ganeshie8):

yes

OpenStudy (kittiwitti1):

oh, okay! 0-0

OpenStudy (kittiwitti1):

what about the others though x.x

OpenStudy (kittiwitti1):

I only need one really!

OpenStudy (kittiwitti1):

http://prntscr.com/98a0in problems

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