According to the synthetic division below, which of the following statements are true? Check all that apply. 2(3 -11 10) 6 -10 ____________ 3 -5 0 A. (3x2 - 11x + 10) (x - 2) = (3x - 5) B. (3x2 - 11x + 10) (x + 2) = (3x - 5) C. (x - 2) is a factor of 3x2 - 11x + 10. D. (x + 2) is a factor of 3x2 - 11x + 10. E. The number -2 is a root of F(x) = 3x2 - 11x + 10. F. The number 2 is a root of F(x) = 3x2 - 11x + 10.
\[\frac{P(x)}{x-c}=Q(x)+\frac{R}{x-c} \\ \\ \text{ where } Q(x) \text{ is quotient } \\ \text{ and } R \text{ is remainder } \\ \text{ if } R=0 \text{ then } (x-c) \text{ divides } P(x) \\ \text{ and both } (x-c) \text{ and } Q(x) \text{ are factors of } P(x) \\ \text{ and so } P(x)=Q(x)(x-c) \\ \text{ also } x=c \text{ is a root since when } x=c \text{ we have } P(c)=Q(c)(c-c)=0 \\ \]
would that be a?
your goona have to dumb that down for me
the remainder is the number left over in the division
what number is leftover in your division above
would'nt it be 3, -5, 0
no
the remainder is not 3 different numbers
the number left over is the last number in the last column
so 0
yep so we do have R=0 that is the remainder is 0 just apply the other things I mentioned above
can you identify what P(x) is and what c is
and what Q(x) is
so the answers for the questions would be A, C, and F
A is not correct unless you made a type-o in A
ok not A what about the rest
so there isn't a type-o in A? you wrote A exactly as it was written in your worksheet or whatever you are getting these questions from?
(3x^2-11x+10)/(x-2)=3x-5 would have been right but (3x^2-11x+10)(x-2)=3x-5 is totally not true
\[\frac{P(x)}{x-c}=Q(x)+\frac{R}{x-c}\] |dw:1448837892960:dw| so you are right C and F are definitely true but I'm still concerned you have mistyped A
so would b be right
no a 2nd deg polynomial times a 1st degree polynomial is a 3rd deg polynomial not a first degree polynomial did you read what I said? I think there is a type-0 in A I showed you by changing the operation from times to division would make A correct
for example x^2*x is x^3 this would not magically end up being x
unless you had x^2/x which is x
did you read what I typed earlier which was this: "(3x^2-11x+10)/(x-2)=3x-5 would have been right but (3x^2-11x+10)(x-2)=3x-5 is totally not true "
i checked it there was a typo sorry A. (3x2 - 11x + 10) / (x - 2) = (3x - 5)
ok
so you do have 3 answers then
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