if cscx=2 and x is in quadrant 2 then sin(2x)=
what is csc ?
I need to know what you know so I can help you properly
csc = 2 csc= 1/sin uhh I dont really have any other info
oh and it would be hypotenuse/opposite
okay, csc is the inverse of sin like you said \(csc = \large \frac{1}{sin} \)
Yes
so it is possible to think it like \(\large \frac{1}{sin~x} = 2 \)
so if that is possible, it is also possible to think of other trigonometric identities. yes?
Yes I think so
so tell me, what other trigonometric identities do you know or you're familiar with
sin(2x)=2sinxcosx and I think that is important to know in this equation
I used the wrong word. I said inverse, when I meant to use RECIPROCAL.
YES! you can use something like that
its okay same thing basically? Okay well I am not seeing how it can be used, I just though it would fit since we have the sin(2x)=
so basically cscx=1/2sinxcox
which leads me to thinking that sin(2x)=1/2 when cscx=2
cosx*
does the word quadrant ring any bell?
yes, and in the second quadrant- isnt everything positive?
hmm?
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Oh, wait sin is positive and cos is negative
so then sin(2x)= -1/2 ??
don't be confused okay? isn't sin your y also cos is x this is why tan = sin/cos = y/x = slope
Yes I know this.
so csc=1/x
are you thinking like this? 1/x = 2 x = 1/2 so \(sin ~(2 \large \frac{1}{2}) = \)
ohhh i see. I didn't think that far ahead. Thanks then. So now we just do (2)(1/2) which is 1
sorry my connection keeps lagging
so sin(1)??
alright, now I am slightly lost.
do not be lost this just requires some practice of fiddling with trig identities and being really familiar with them
okay well now what can we do using the sin(1)
I am actually stuck now, what can I do?
google brought up: https://answers.yahoo.com/question/index?qid=20130805043703AAfAth7 which has the solution
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