Question

I need help understanding how to write an equation from point-slope to standard form

Answer 1

point slope form is \(y - y_1 = m(x - x_1)\)
and standard form is \(ax + by = c\)

Answer 2

this might seem a little confusing
but all you really have to do is
distribute the slope (m)
then add/subtract #x to both sides
to bring it to the side that y is on

Answer 3

for example

if you have
y - 2 = 3(x - 1) as point-slope form
y - 2 = 3x - 3 distribute the 3
-3x -3x minus 3x from both sides
----------------------
-3x + y - 2 = -3
+2 +2 then add 2 to both sides (to get the variables alone)
---------------------
-3x + y = -1 which is now in standard form :)

do you see how that worked?

Answer 4

can you give me an example with a negative ordered pair

Answer 5

and also thank you i do understand your explaination

Answer 6

you mean a negative ordered pair such as
y + 2 = 3(x + 1)
?

Answer 7

yes but preferably one with only one negative coordinate

Answer 8

y - 8 = -4(x + 3)
y - 8 = -4x - 12
4x + y - 8 = -12
4x + y= -4