Question

what is t^2+12t-18 in vertex form? with steps please.

Answer 1

formula to find x-coordinate of the vertex \[\large\rm x=\frac{ -b }{ 2a}\]
and then substitute x value into the equation to find y-coordinate
Ax^2+Bx+C
where a=leading coefficient
and b=coefficient of x term
c=constant

Answer 2

i thought that equation gave you the slope?

Answer 3

which equation ??

Answer 4

\[x=-b/2a\]

Answer 5

(x2-x1)/(y2-y1 or smething gives you slope. this gives you the value of X,
for vertex form you're looking for the formula of y=a(x-h)^2+k

Answer 6

no slope formula is different
that's -b/2a to find x-coordinate of the vertex

Answer 7

or you can rewrite the equation in vertex form by completing the square

Answer 8

how do you do that complete the square?

Answer 9

http://mathbitsnotebook.com/Algebra1/Quadratics/QDVertexForm.html

Answer 10

explains it really well.

Answer 11

i need to put t^2+12t-18 in vertex form by completing the square. i just reread the question.

Answer 12

oh so rewrite in vertex form
i thought find the vertex

Answer 13

idk how to do that

Answer 14

do you mean the x=-b/2a thing?

Answer 15

no well that's the formula to find x-coordinate of the vertex forget about it you need to rewrite the equation in vertex form by completing the square
first step we need to get 1 for leading coefficient in order to complete the square

Answer 16

what do you mean?

Answer 17

\[\large\rm y=t^2+12t-18\]
in this equation a=1 so we can complete the square
take half of x term and then add (b/2)^2 to both sides

Answer 18

what do you mean what ?

Answer 19

so the new equation is .5t^2+6t-9?

Answer 20

no vertex form should be like this y=a(x-h)^2+k

Answer 21

wait the x term is 6 so half that is 3... so the new equation is y=1(3-h)^2+k

Answer 22

y=1(3(-6))^2+(-54)

Answer 23

hello?

Answer 24

@Nnesha are you still there?

Answer 25

no sorry i was afk

Answer 26

how did you get -6 and we should keep the x variable

Answer 27

\[\large\rm y=t^2+12t-18\]
in this equation a=1 so we can complete the square
-18 is constant
first we need to find perfect trinomail \[\rm y =(\color{Red}{t^2+12t}) -18\]
now take half of x term and then square it
(b/2)^2 add in the parentheses and subtract from constant term

Answer 28

let me know if you have a question so far