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OpenStudy (anonymous):
Algebra 2A help please! Find the pH level, to the nearest tenth, of a liquid with [H+] about 3.2x10^-2 a. -2.5 b. 2.5 c. -1.5 d. 1.5 Please and thank you.
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OpenStudy (anonymous):
@satellite73
Directrix (directrix):
pH = - log [H+] pH = - log ( 3.2 * 10^(-2) ) pH = - log 3.2 - log 10 ^ (-2) pH = -.505 - (-2) pH = -.51 + 2 pH = 1.49 or 1.5 @fatkat222
OpenStudy (denisaboichuk):
b
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