Question

@misty1212 What are the zero(s) of the function f(x) = the quantity of 4 x squared minus 36 x, all over x minus 9?

x = −9
x = 0
x = 9
x = 0 and x = 9

Answer 1

\[f(x) = \frac{ 4x^2-36x }{ x - 9 }\]

Answer 2

@satellite73

Answer 3

@satellite73

Answer 4

HI
let me get rid of this bozo hold on

Answer 5

as flapperreaper

Answer 6

@misty1212 lol okay.. and my answer to this is x = 0 ..

Answer 7

\[f(x) = \frac{ 4x^2-36x }{ x - 9 }\]
\[f(x) = \frac{ 4x(x-9) }{ x - 9 }=4x\]

Answer 8

you are right, zero is at \(0\)

Answer 9

ok yay thanks :) ..

Answer 10

\[\color\magenta\heartsuit\]