for the system shown below, what are the coordinates of the solution that lies in quadrant I?

3y^2-5x^2=8
3y^2-x^2=24
@ganeshie8 @pooja195 @ParthKohli @Kainui

Question

for the system shown below, what are the coordinates of the solution that lies in quadrant I? 

3y^2-5x^2=8
3y^2-x^2=24
@ganeshie8 @pooja195 @ParthKohli @Kainui

anonymous · Answer

attachment

anonymous · Answer

@Nnesha

nnesha · Answer

use the elimination method

anonymous · Answer

how do I do that?

nnesha · Answer

for elimination method you need to get same coefficient for one of the variable with opposite sign

nnesha · Answer

3y^2-5x^2=8
3y^2-x^2=24
3y^2 is same to cancel it out you should multiply one of the equation by negative one

anonymous · Answer

ok I did that now what do I do next?

nnesha · Answer

then eliminate 
did you multiply first or 2nd equation by one ??

anonymous · Answer

the first one

nnesha · Answer

alright( 3y^2-5x^2=8 ) times -1 
what did you get after multiplying by -1 ?

anonymous · Answer

thats were I'm stuck I can't get an answer

nnesha · Answer

well you will not get the answer by just multiplying the equation by -1

nnesha · Answer

$$\rm -1(3y^2-5x^2=8)$$ distribute parentheses by negative one let me now what yo uget

nnesha · Answer

multiply all terms in the parentheses by negative one

nnesha · Answer

and if you don't want to do any work then you can use calculator :/ https://www.desmos.com/ type both equations