Question

evaluate 14 sigma n=1 3n+2? 39 49 340 343

Answer 1

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Answer 2

You posted thia in wrong section

Answer 3

Try posting in math section

Answer 4

Hello! Welcome to OpenStudy! This would probably fit better in the Math section
http://openstudy.com/study#/groups/Mathematics

Answer 5

\[\sum_{n=1}^{14} 3n+2\] do you mean this

Answer 6

You can simply sum it up by plugging n = 1 where there is a n in your equation 3n+2, so [3(1)+2] + [3(2)+2] up to 14 times :P maybe that would be good practice for you!

Answer 7

Yea I am sorry I wrote it wrong. @Astrophysics

Answer 8

Idk how to do it can u help me plz

Answer 9

The sigma sign means to add everything up, so you start at n = 1 and end at n = 14

Answer 10

my options are
a.39
b.49
c.340
d.343

Answer 11

Cool, but you have to do it as I showed you above

Answer 12

how can u give me an example

Answer 13

\[\sum_{n=1}^{3} 3n+2 \implies [3(1)+2]+[3(2)+2]+[3(3)+2] = 24\]

Answer 14

That's from n = 1 to n = 3