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OpenStudy (chris215):
jimthompson5910 (jim_thompson5910):
are you able to use the chain rule?
jimthompson5910 (jim_thompson5910):
You should find that
\[\Large h(x) = g[f(x)]\]
\[\Large h \ '(x) = g \ '[f(x)]*f \ '(x)\]
after using the chain rule. Now plug in x = 1
OpenStudy (unklerhaukus):
@chris215, do you understand what @jim_thompson5910 has said?
OpenStudy (chris215):
i think.. when I plugged in 1 for x I got 0
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jimthompson5910 (jim_thompson5910):
what is f(1) equal to?
OpenStudy (chris215):
im not sure
jimthompson5910 (jim_thompson5910):
look at the table
find where x = 1
then look up the value of f(x)
OpenStudy (chris215):
so 3?
jimthompson5910 (jim_thompson5910):
yes, f(1) = 3
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jimthompson5910 (jim_thompson5910):
\[\Large h \ '(x) = g \ '[f(x)]*f \ '(x)\]
\[\Large h \ '(1) = g \ '[f(1)]*f \ '(1)\]
\[\Large h \ '(1) = g \ '[\color{red}{f(1)}]*f \ '(1)\]
\[\Large h \ '(1) = g \ '(\color{red}{3})*f \ '(1)\]
jimthompson5910 (jim_thompson5910):
now you just need to find `g ' (3)` and `f ' (1) ` in the table. Then multiply
OpenStudy (chris215):
ok so is it 6?
jimthompson5910 (jim_thompson5910):
how are you getting 6?
tell me what you're getting for `g ' (3)` and `f ' (1) `
OpenStudy (chris215):
oh sorry 18
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jimthompson5910 (jim_thompson5910):
and how did you get 18?
OpenStudy (chris215):
f'(1)=2 and g'(3)=9 right? then multiply?
jimthompson5910 (jim_thompson5910):
yep you nailed it
jimthompson5910 (jim_thompson5910):
\[\Large h \ '(1) = 18\]
is your final answer
OpenStudy (chris215):
thanks so much!!
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