Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (chris215):

-

OpenStudy (chris215):

jimthompson5910 (jim_thompson5910):

are you able to use the chain rule?

jimthompson5910 (jim_thompson5910):

You should find that \[\Large h(x) = g[f(x)]\] \[\Large h \ '(x) = g \ '[f(x)]*f \ '(x)\] after using the chain rule. Now plug in x = 1

OpenStudy (unklerhaukus):

@chris215, do you understand what @jim_thompson5910 has said?

OpenStudy (chris215):

i think.. when I plugged in 1 for x I got 0

jimthompson5910 (jim_thompson5910):

what is f(1) equal to?

OpenStudy (chris215):

im not sure

jimthompson5910 (jim_thompson5910):

look at the table find where x = 1 then look up the value of f(x)

OpenStudy (chris215):

so 3?

jimthompson5910 (jim_thompson5910):

yes, f(1) = 3

jimthompson5910 (jim_thompson5910):

\[\Large h \ '(x) = g \ '[f(x)]*f \ '(x)\] \[\Large h \ '(1) = g \ '[f(1)]*f \ '(1)\] \[\Large h \ '(1) = g \ '[\color{red}{f(1)}]*f \ '(1)\] \[\Large h \ '(1) = g \ '(\color{red}{3})*f \ '(1)\]

jimthompson5910 (jim_thompson5910):

now you just need to find `g ' (3)` and `f ' (1) ` in the table. Then multiply

OpenStudy (chris215):

ok so is it 6?

jimthompson5910 (jim_thompson5910):

how are you getting 6? tell me what you're getting for `g ' (3)` and `f ' (1) `

OpenStudy (chris215):

oh sorry 18

jimthompson5910 (jim_thompson5910):

and how did you get 18?

OpenStudy (chris215):

f'(1)=2 and g'(3)=9 right? then multiply?

jimthompson5910 (jim_thompson5910):

yep you nailed it

jimthompson5910 (jim_thompson5910):

\[\Large h \ '(1) = 18\] is your final answer

OpenStudy (chris215):

thanks so much!!

jimthompson5910 (jim_thompson5910):

np

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!