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OpenStudy (anonymous):
If you have 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, which element is the reactant in excess?
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OpenStudy (jfraser):
you need to start by looking at the balanced reaction. Have you got one?
OpenStudy (anonymous):
The balanced eqn will be: N2 + 3H2 = 2NH3. Thus, for every mol of N2 you need 3 mol H2. Which means that for 5 mol N2 you need 15 mol. Thus H2 is the limiting reagent.
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