Find the value of k that makes the inequality
2kx-3k<2x+4+3kx
have no solution.
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OpenStudy (anonymous):
@adamaero You are the first person to at least look -_-, thanks
OpenStudy (adamaero):
Did you try plugging in numbers?
OpenStudy (anonymous):
yeah, but i get stuck with the x
for instance, when I plugged in 1, I got
-3x<7
OpenStudy (anonymous):
So far, all I could simplify the equation to is -kx-3k<2x-4
OpenStudy (freckles):
did you try solving for x
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OpenStudy (anonymous):
No, because k will be in the way
OpenStudy (freckles):
and then look at the domain restrictions for k afterwards
OpenStudy (freckles):
put all of your x's on onside and all your things that don't have x in it on the other
OpenStudy (freckles):
let me know when you have done this
OpenStudy (anonymous):
;-;
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OpenStudy (freckles):
\[2kx-3k<2x+4+3kx \\ \text{ subtracting } 3kx \text{ on both sides } \\ -kx-3k<2x+4\]
how did your 4 end up being -4 ?
OpenStudy (anonymous):
It didn't, sorry, copied it wrong.
OpenStudy (freckles):
ok well we are attempting to isolate x
we need to subtract 2x on both sides and add 3k on both sides
OpenStudy (anonymous):
that wont do much...
OpenStudy (anonymous):
but contine
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OpenStudy (anonymous):
*continue
OpenStudy (freckles):
\[-kx-2x<3k+4 \\ x(-k-2)<3k+4 \\ \text{ if } -k-2>0 \text{ then } x<\frac{3k+4}{-k-2} \\ \\ \text{ if } -k-2<0 \text{ then } x> \frac{3k+4}{-k-2}\]
anyways in either inequality k cannot be...
OpenStudy (anonymous):
oh i see, so you could factor x
OpenStudy (freckles):
yep that is why I asked you to put all your x terms on one side and terms without x on the other side
OpenStudy (anonymous):
however, I can't find k while x itself is still an inequality.
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OpenStudy (freckles):
? you do know you cannot divide by 0 right?
OpenStudy (freckles):
so k cannot be
OpenStudy (freckles):
-k-2 is zero when k is?
OpenStudy (anonymous):
however is k was zero, 0-2 is negative two, which you can divide by
OpenStudy (anonymous):
2
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OpenStudy (freckles):
well if k=-2 then -k-2 is 0
OpenStudy (anonymous):
oh xD
OpenStudy (freckles):
see what happens when you plug it into your original inequality
OpenStudy (anonymous):
oh, that makes sense!
OpenStudy (freckles):
the inequality will definitely not have a solution when k=-2
\[2(-2)x-3(-2)<2x+4+3(-2)x \\ -4x+6<2x+4-6x \\ -4x+6<-4x+4\]
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OpenStudy (anonymous):
plus to both sides 4x
then 6 is not greater than 4
OpenStudy (freckles):
solve the inequality for when k=-2
you will see great fail
OpenStudy (freckles):
great
OpenStudy (anonymous):
TYVM
OpenStudy (freckles):
np
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OpenStudy (freckles):
one more thing ...
OpenStudy (freckles):
if the inequality was switched
they might have asked for which k does the inequality hold for all x
OpenStudy (freckles):
because you would have winded up with 6>4
OpenStudy (freckles):
which would be try for all x
OpenStudy (freckles):
just for fun I thought I would mention that
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