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Mathematics 8 Online
OpenStudy (anonymous):

Find the value of k that makes the inequality 2kx-3k<2x+4+3kx have no solution.

OpenStudy (anonymous):

@adamaero You are the first person to at least look -_-, thanks

OpenStudy (adamaero):

Did you try plugging in numbers?

OpenStudy (anonymous):

yeah, but i get stuck with the x for instance, when I plugged in 1, I got -3x<7

OpenStudy (anonymous):

So far, all I could simplify the equation to is -kx-3k<2x-4

OpenStudy (freckles):

did you try solving for x

OpenStudy (anonymous):

No, because k will be in the way

OpenStudy (freckles):

and then look at the domain restrictions for k afterwards

OpenStudy (freckles):

put all of your x's on onside and all your things that don't have x in it on the other

OpenStudy (freckles):

let me know when you have done this

OpenStudy (anonymous):

;-;

OpenStudy (freckles):

\[2kx-3k<2x+4+3kx \\ \text{ subtracting } 3kx \text{ on both sides } \\ -kx-3k<2x+4\] how did your 4 end up being -4 ?

OpenStudy (anonymous):

It didn't, sorry, copied it wrong.

OpenStudy (freckles):

ok well we are attempting to isolate x we need to subtract 2x on both sides and add 3k on both sides

OpenStudy (anonymous):

that wont do much...

OpenStudy (anonymous):

but contine

OpenStudy (anonymous):

*continue

OpenStudy (freckles):

\[-kx-2x<3k+4 \\ x(-k-2)<3k+4 \\ \text{ if } -k-2>0 \text{ then } x<\frac{3k+4}{-k-2} \\ \\ \text{ if } -k-2<0 \text{ then } x> \frac{3k+4}{-k-2}\] anyways in either inequality k cannot be...

OpenStudy (anonymous):

oh i see, so you could factor x

OpenStudy (freckles):

yep that is why I asked you to put all your x terms on one side and terms without x on the other side

OpenStudy (anonymous):

however, I can't find k while x itself is still an inequality.

OpenStudy (freckles):

? you do know you cannot divide by 0 right?

OpenStudy (freckles):

so k cannot be

OpenStudy (freckles):

-k-2 is zero when k is?

OpenStudy (anonymous):

however is k was zero, 0-2 is negative two, which you can divide by

OpenStudy (anonymous):

2

OpenStudy (freckles):

well if k=-2 then -k-2 is 0

OpenStudy (anonymous):

oh xD

OpenStudy (freckles):

see what happens when you plug it into your original inequality

OpenStudy (anonymous):

oh, that makes sense!

OpenStudy (freckles):

the inequality will definitely not have a solution when k=-2 \[2(-2)x-3(-2)<2x+4+3(-2)x \\ -4x+6<2x+4-6x \\ -4x+6<-4x+4\]

OpenStudy (anonymous):

plus to both sides 4x then 6 is not greater than 4

OpenStudy (freckles):

solve the inequality for when k=-2 you will see great fail

OpenStudy (freckles):

great

OpenStudy (anonymous):

TYVM

OpenStudy (freckles):

np

OpenStudy (freckles):

one more thing ...

OpenStudy (freckles):

if the inequality was switched they might have asked for which k does the inequality hold for all x

OpenStudy (freckles):

because you would have winded up with 6>4

OpenStudy (freckles):

which would be try for all x

OpenStudy (freckles):

just for fun I thought I would mention that

OpenStudy (freckles):

so it was an all or none situation

OpenStudy (freckles):

if that makes sense

OpenStudy (freckles):

true* not try

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