Ask your own question, for FREE!
Mathematics 23 Online
OpenStudy (newwar):

Which is the equation of the given line in slope-intercept form? 1.https://static.k12.com/bank_packages/files/media/mathml_d7897c0504559c47de18da3fffe2fff6fef4fa4c_1.gif 2.https://static.k12.com/bank_packages/files/media/mathml_ead3310e27431974f2cf8e9e71a4a538fd98f568_1.gif 3. https://static.k12.com/bank_packages/files/media/mathml_bf96d585e5ccd2e74d355383586d1b47bac38b6c_1.gif 4.https://static.k12.com/bank_packages/files/media/mathml_d4f88b456d580d09848ccb3494e7534488608315_1.gif https://static.k12.com/calms_media/media/1312500_1313000/1312645/1/269940bb37befc5628fb49bd3d16afbb

OpenStudy (newwar):

@KendrickLamar2014

OpenStudy (newwar):

@Hayhayz @ItsOnlyADream @Agl202

OpenStudy (newwar):

@Jamierox4ev3r

OpenStudy (newwar):

@BioHazard9064

OpenStudy (biohazard9064):

to be honest this is not the best way to get help

OpenStudy (biohazard9064):

but luckily i know someone who can help

OpenStudy (biohazard9064):

@pooja195 can you help

pooja195 (pooja195):

Slope intercept form = \(\huge\rm\bf\color{red}{y=mx+b}\)

pooja195 (pooja195):

I can view the last link

pooja195 (pooja195):

OK so first we need to fine the slope \[\LARGE \frac{y_2-y_1}{x_2-x_1}=slope\] \[\LARGE \frac{5--3}{1-1}=slope\] \[\LARGE \frac{5+3}{-1-1}=slope\]

OpenStudy (newwar):

do i find the slope for each one

pooja195 (pooja195):

Nope just the last one

pooja195 (pooja195):

The rest are just steps

OpenStudy (newwar):

ok

OpenStudy (newwar):

2

OpenStudy (newwar):

slope 2

pooja195 (pooja195):

Hmm its actually ... OK so first we need to fine the slope \[\LARGE \frac{y_2-y_1}{x_2-x_1}=slope\] \[\LARGE \frac{-3-5}{1--1}=slope\] \[\LARGE \frac{-3-5}{1+1}=-8/2=-4\]

pooja195 (pooja195):

Which of your options has a slope of -4?

OpenStudy (newwar):

b dose

pooja195 (pooja195):

Good now we know the answer :)

OpenStudy (newwar):

thank you so much

pooja195 (pooja195):

yw ^_^

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!