At what angle (in degrees) does first-order diffraction from layers of atoms 161.0 pm apart occur, using x rays with a wavelength of 147 pm?

Question

jadedry · Answer

You have to use Bragg's diffraction equation:

$$n*\lambda = 2d*\sin \theta$$

where n = the order of the diffraction. In this case, it equals 1. 

Lamba = 147 pm or 1.47 * 10^10 m

D = 161 pm or 1.61 *10^10m

Sin theta is the variable you have to solve for.

$$1 * 1.47*10^{10} = 1.61*10^{10} *2  * \sin \theta$$

$$0.45652 = \sin \theta$$

Angle of diffraction = 27.16 degrees

yb1996 · Answer

Thank You!!!