Complete the square then rewrite as a perfect square. HELP PLS

1. z^2 - 19z + ? = 0

Question

Complete the square then rewrite as a perfect square. HELP PLS

1. z^2 - 19z + ? = 0

anonymous · Answer

takes two steps 
what is half of 19 (answer as a fraction)

joshoyen · Answer

oh wait i got that part i just need help rewriting it as a perfect square

joshoyen · Answer

it is z^2-19z+90.25=0

anonymous · Answer

actually question is unclear 
but maybe they just want $$\left(z-\frac{19}{2}\right)^2=0$$

joshoyen · Answer

wait no you got it right, my answer sheet says 361/4; (z-19/2)^2

anonymous · Answer

ok

joshoyen · Answer

how did you get that though, i dont know the steps into rewriting it as ap erfect square

anonymous · Answer

half of $19$ is $\frac{19}{2}$ and $\left(\frac{19}{2}\right)^2=\frac{361}{4}$

anonymous · Answer

don't muck around with decimals

anonymous · Answer

Actually it tends to be confusing, what really is the value of that question mark? Is it another variable or it's just the same as z or it has a numerical value?

joshoyen · Answer

wait so what would be the rewritten perfect square form for a^2+14a+49=0?

anonymous · Answer

half of 14 is 7 and $7^2=19$ so $$a^2+14a+49=(a+7)^2$$

anonymous · Answer

whoops meant to say $7^2=49$ but you get the idea

joshoyen · Answer

alright thanks a lot!

joshoyen · Answer

Wait can I get one more problem? What would p^2 + 3p + ? be?