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need help with this series problem
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\[\sum_{k=1}^{\infty} \frac{ 3^{k} }{ k! k }\]
and use the limit comparison test please
@zepdrix @freckles
i got this one wrong on a test :(
are you testing convergence ?
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not sure
whats the exact question ?
use the limit comparison test to establish convergence or divergence series
Ohk... you may use below geometric series for comparison : \[\sum\limits_{k=1}^{\infty} \dfrac{3^k}{4^k}\]
okay thats a geometric series right?
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and its less than one so the whole series converges right?
Yes, since \(r = \dfrac{3}{4}\lt 1\), it converges. compare that with your series
okay i'll draw it out |dw:1449033990462:dw|
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