Paige is a graphic designer who makes logos for companies. She makes a design for a logo, which is in the shape of a square. The design of this logo is drawn on the coordinate plane as square ABCD. She then dilates this logo by a scale factor of 2, forming square A'B'C'D'. She realizes that she needs a much bigger design and so further dilates this transformed square by a scale factor of 3 to form A"B"C"D". What are the coordinates of vertex A' and vertex C"? A'(-10, -4) and C''(-6, -8) A'(-10, -4) and C"(-18, -24) A'(-30, -12) and C"(-18, -24) A'(-30, -12) and C"(-4, -6) A'(-10, -4) an
https://cdn.ple.platoweb.com/EdAssets/97ef42e5bba844f5bbe127535836379c?ts=635591394084170000
i guess nobodies smart enough to do this
Look at the given graph. What are the coordinates of A ? |dw:1449069216809:dw|
-5,-2
good, you get A' by dilating that by a factor of 2
in order to dilate by a factor of 2, simply multiply each coordinate by 2
what do you get when you multiply each coordinate of A by 2 ?
so multiply -5,-2
multiply each of them by 2
-5*2, -2*2 -10, -4
so A' = (-10, -4)
is that clear ?
yea thanks can u help with more
Triangle XYZ, with vertices X(-1, -3), Y(-1, -1), and Z(-3, -1), is translated 2 units right and one unit down to form triangle X′Y′Z′. What are the coordinates of the vertices of triangle X′Y′Z′? X′(1, 4), Y′(1, -2), and Z′(-1, 0) X′(1, -4), Y′(1, -2), and Z′(-1, -2) X′(-1, 4), Y′(-1, 2), and Z′(1, 0) X′(1, -4), Y′(1, -2), and Z′(-1, 0) X′(-3, -4), Y′(-3, -2), and Z′(-5, -2)
hey before that, have you figured out A'' in first problem ?
yea
what did u get ?
a
a is wrong
you need to multiply the coordinates of A' by 3
A' = (-10, -4) A'' = (-10*3, -4*3) = (-30, -12)
so C
nope
could you post your options again
there was an issue while you copy pasted
Triangle XYZ, with vertices X(-1, -3), Y(-1, -1), and Z(-3, -1), is translated 2 units right and one unit down to form triangle X′Y′Z′. What are the coordinates of the vertices of triangle X′Y′Z′? X′(1, 4), Y′(1, -2), and Z′(-1, 0) X′(1, -4), Y′(1, -2), and Z′(-1, -2) X′(-1, 4), Y′(-1, 2), and Z′(1, 0) X′(1, -4), Y′(1, -2), and Z′(-1, 0) X′(-3, -4), Y′(-3, -2), and Z′(-5, -2)
A'(-10, -4) and C''(-6, -8) A'(-10, -4) and C"(-18, -24) A'(-30, -12) and C"(-18, -24) A'(-30, -12) and C"(-4, -6) A'(-10, -4) an
something is missing, look at last option
it was not pasted properly
oh i can't go back becuz i already chose an answer
can u help with this one now Triangle XYZ, with vertices X(-1, -3), Y(-1, -1), and Z(-3, -1), is translated 2 units right and one unit down to form triangle X′Y′Z′. What are the coordinates of the vertices of triangle X′Y′Z′? X′(1, 4), Y′(1, -2), and Z′(-1, 0) X′(1, -4), Y′(1, -2), and Z′(-1, -2) X′(-1, 4), Y′(-1, 2), and Z′(1, 0) X′(1, -4), Y′(1, -2), and Z′(-1, 0) X′(-3, -4), Y′(-3, -2), and Z′(-5, -2)
2 units right so add 2 to the x coordinates
one unit down so subtract 1 to the y coordiantes
X = (-1, -3) X' = (-1+2, -3-1) = (1, -4)
see if you can find Y' similarly
@mrgray
1,-2
Yes!
what about Z'
is it -1,0
Perfect!
ok so its D
i got 10 more can u help
@ganeshie8
il try, post
A 90° counterclockwise rotation about the origin, and then a reflection across the x-axis performed on shape I proves that shape II is congruent to shape I. Which other sequences of transformations on shape I can also be used to prove congruence to shape II? a reflection across the y-axis and a 90° clockwise rotation about the origin a 90° counterclockwise rotation about the origin and a reflection across the y-axis a reflection across the y-axis and a 90° counterclockwise rotation about the origin a 90° clockwise rotation about the origin and a reflection across the x-axis a reflection across the x-axis and a 90° clockwise rotation about the origin
https://cdn.ple.platoweb.com/EdAssets/61e152e2ebbb47f083359266abd86128?ts=635603555664070000
I think it is a reflection across the y-axis and a 90° counterclockwise rotation about the origin
Join our real-time social learning platform and learn together with your friends!