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Mathematics 14 Online
OpenStudy (anonymous):

Paige is a graphic designer who makes logos for companies. She makes a design for a logo, which is in the shape of a square. The design of this logo is drawn on the coordinate plane as square ABCD. She then dilates this logo by a scale factor of 2, forming square A'B'C'D'. She realizes that she needs a much bigger design and so further dilates this transformed square by a scale factor of 3 to form A"B"C"D". What are the coordinates of vertex A' and vertex C"? A'(-10, -4) and C''(-6, -8) A'(-10, -4) and C"(-18, -24) A'(-30, -12) and C"(-18, -24) A'(-30, -12) and C"(-4, -6) A'(-10, -4) an

OpenStudy (anonymous):

i guess nobodies smart enough to do this

ganeshie8 (ganeshie8):

Look at the given graph. What are the coordinates of A ? |dw:1449069216809:dw|

OpenStudy (anonymous):

-5,-2

ganeshie8 (ganeshie8):

good, you get A' by dilating that by a factor of 2

ganeshie8 (ganeshie8):

in order to dilate by a factor of 2, simply multiply each coordinate by 2

ganeshie8 (ganeshie8):

what do you get when you multiply each coordinate of A by 2 ?

OpenStudy (anonymous):

so multiply -5,-2

ganeshie8 (ganeshie8):

multiply each of them by 2

ganeshie8 (ganeshie8):

-5*2, -2*2 -10, -4

ganeshie8 (ganeshie8):

so A' = (-10, -4)

ganeshie8 (ganeshie8):

is that clear ?

OpenStudy (anonymous):

yea thanks can u help with more

OpenStudy (anonymous):

Triangle XYZ, with vertices X(-1, -3), Y(-1, -1), and Z(-3, -1), is translated 2 units right and one unit down to form triangle X′Y′Z′. What are the coordinates of the vertices of triangle X′Y′Z′? X′(1, 4), Y′(1, -2), and Z′(-1, 0) X′(1, -4), Y′(1, -2), and Z′(-1, -2) X′(-1, 4), Y′(-1, 2), and Z′(1, 0) X′(1, -4), Y′(1, -2), and Z′(-1, 0) X′(-3, -4), Y′(-3, -2), and Z′(-5, -2)

ganeshie8 (ganeshie8):

hey before that, have you figured out A'' in first problem ?

OpenStudy (anonymous):

yea

ganeshie8 (ganeshie8):

what did u get ?

OpenStudy (anonymous):

a

ganeshie8 (ganeshie8):

a is wrong

ganeshie8 (ganeshie8):

you need to multiply the coordinates of A' by 3

ganeshie8 (ganeshie8):

A' = (-10, -4) A'' = (-10*3, -4*3) = (-30, -12)

OpenStudy (anonymous):

so C

ganeshie8 (ganeshie8):

nope

ganeshie8 (ganeshie8):

could you post your options again

ganeshie8 (ganeshie8):

there was an issue while you copy pasted

OpenStudy (anonymous):

Triangle XYZ, with vertices X(-1, -3), Y(-1, -1), and Z(-3, -1), is translated 2 units right and one unit down to form triangle X′Y′Z′. What are the coordinates of the vertices of triangle X′Y′Z′? X′(1, 4), Y′(1, -2), and Z′(-1, 0) X′(1, -4), Y′(1, -2), and Z′(-1, -2) X′(-1, 4), Y′(-1, 2), and Z′(1, 0) X′(1, -4), Y′(1, -2), and Z′(-1, 0) X′(-3, -4), Y′(-3, -2), and Z′(-5, -2)

OpenStudy (anonymous):

A'(-10, -4) and C''(-6, -8) A'(-10, -4) and C"(-18, -24) A'(-30, -12) and C"(-18, -24) A'(-30, -12) and C"(-4, -6) A'(-10, -4) an

ganeshie8 (ganeshie8):

something is missing, look at last option

ganeshie8 (ganeshie8):

it was not pasted properly

OpenStudy (anonymous):

oh i can't go back becuz i already chose an answer

OpenStudy (anonymous):

can u help with this one now Triangle XYZ, with vertices X(-1, -3), Y(-1, -1), and Z(-3, -1), is translated 2 units right and one unit down to form triangle X′Y′Z′. What are the coordinates of the vertices of triangle X′Y′Z′? X′(1, 4), Y′(1, -2), and Z′(-1, 0) X′(1, -4), Y′(1, -2), and Z′(-1, -2) X′(-1, 4), Y′(-1, 2), and Z′(1, 0) X′(1, -4), Y′(1, -2), and Z′(-1, 0) X′(-3, -4), Y′(-3, -2), and Z′(-5, -2)

ganeshie8 (ganeshie8):

2 units right so add 2 to the x coordinates

ganeshie8 (ganeshie8):

one unit down so subtract 1 to the y coordiantes

ganeshie8 (ganeshie8):

X = (-1, -3) X' = (-1+2, -3-1) = (1, -4)

ganeshie8 (ganeshie8):

see if you can find Y' similarly

ganeshie8 (ganeshie8):

@mrgray

OpenStudy (anonymous):

1,-2

ganeshie8 (ganeshie8):

Yes!

ganeshie8 (ganeshie8):

what about Z'

OpenStudy (anonymous):

is it -1,0

ganeshie8 (ganeshie8):

Perfect!

OpenStudy (anonymous):

ok so its D

OpenStudy (anonymous):

i got 10 more can u help

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

il try, post

OpenStudy (anonymous):

A 90° counterclockwise rotation about the origin, and then a reflection across the x-axis performed on shape I proves that shape II is congruent to shape I. Which other sequences of transformations on shape I can also be used to prove congruence to shape II? a reflection across the y-axis and a 90° clockwise rotation about the origin a 90° counterclockwise rotation about the origin and a reflection across the y-axis a reflection across the y-axis and a 90° counterclockwise rotation about the origin a 90° clockwise rotation about the origin and a reflection across the x-axis a reflection across the x-axis and a 90° clockwise rotation about the origin

ganeshie8 (ganeshie8):

I think it is a reflection across the y-axis and a 90° counterclockwise rotation about the origin

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