Question

medal and fan!!!

Answer 1

Meg has a can that contains 80% of orange juice and the rest water. The can has 1 liter of water.

Part A: Write an equation in one variable that can be used to find the total number of liters of orange juice and water in the can. Define the variable used in the equation. (5 points)

Part B: How many liters of orange juice are present in the can? Show your work. (5 points)

Answer 2

Sure. Go ahead and define your variables.

J = Amount of Orange Juice

Shall you define the amount of water?

Answer 3

1 liter?

Answer 4

@tkhunny are you there?

Answer 5

DEFINE it. Don't try to figure out what it is.

Answer 6

what does that mean?

Answer 7

What did I just do with "J" and the Orange Juice?

Answer 8

c=1liter

Answer 9

That's an assignment, not a definition.

Try C = Amount of Water in the can. THAT is a DEFINITION.

Now what?

Answer 10

Write an equation in one variable that can be used to find the total number of liters of orange juice and water in the can

Answer 11

Why are you repeating that. If you know the amount of water (C) and Orange Juice (J) in a can, how do you calculate the PERCENT of Orange Juice?

Answer 12

I don't know i'm sorry

Answer 13

Sure you do. How do you calculate the percent of anything in anything else? It's a division problem.

\(\dfrac{Stuff\;We\;Care\;About}{Total \;Stuff} = Percent\;of\;Stuff\;We\;Care\;About\)

Answer 14

\[\frac{ j }{ c }\]

Answer 15

= percent water in the can?

Answer 16

Not quite. C is just the water. The percent of orange juice is \(\dfrac{J}{C+J}\).

See how that denominator is all the stuff in the can and the numerator is just the stuff we want to talk about?

Answer 17

yeah,i see now

Answer 18

is that all we have to do for part a?

Answer 19

No, that's just how to calculate the percentage. Now, we need to put in what we know.

\(\dfrac{J}{C+J} = 0.80\)

\(\dfrac{J}{C+1.0} = 0.80\)

Better Definition:

J = # of liters of Orange Juice
C = # of liters of Orange Juice = 1.0

Making any sense?

Answer 20

yes

Answer 21

Whoops! Should be \(\dfrac{J}{C+J} = \dfrac{J}{1.0 + J} = 0.80\)

Sorry about that. I substituted for the wrong one.

Solve for J and you're done. :-)

Answer 22

i'm really sorry, i know i sound like a moron but can you teach me how to do that?

Answer 23

You need to be able to do this. You WILL be expected to do it on an exam.

1) Get rid of the denominator. Multiply everything by \((1.0 + J)\). This should leave only \(J\) on the left side and you tell me what on the right side.

Answer 24

c

Answer 25

Left Side

\(\dfrac{J}{1.0 + J}\cdot (1.0 + J) = J\cdot\dfrac{1.0 + J}{1.0 + J} = J*1 = J\)

Right Side

\(0.80\cdot(1.0+J) = \) You tell me. Write down everything you do or think.