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Linear Algebra 18 Online
OpenStudy (dean2291):

Which points are solutions to the system of inequalities shown below? Check all that apply. y > (equal to) x + 3 y < 2x x > 6 A. (8, 12) B. (8, 10) C. (6, 11) D. (7, 10) E. (5, 10) F. (9, 12)

OpenStudy (anonymous):

I showed you how to do these in the last question. Give these a go and I'll check your answers.

OpenStudy (dean2291):

how to do ALL 3

OpenStudy (anonymous):

As we did before, take the x and y value from each coordinate and check it in all 3 inequalities. If they're all true, then that point is a solution to the inequalities.

OpenStudy (mathmale):

You need to graph all three inequalities on the same set of axes. Shade the areas that satisfy the inequalities. Now, one by one, locate the 6 given points. If any is in the most-shaded area, then it's a solution of the system of inequalities. List the points that satisfy all 3 inequalities. Please show your work, so that we can give you meantingful feedback on it.

OpenStudy (dean2291):

can you do this one as an example

OpenStudy (dean2291):

@tom982

OpenStudy (mathmale):

We need YOUR input. Please graph the following on the same set of axes: y < 2x x > 6 Use the Draw utility (below);.|dw:1449085528674:dw|

OpenStudy (mathmale):

Mark scale divisions on the x- and y-axes. To graph y < 2x first graph the line y=2x and then shade the area BELOW that line.

OpenStudy (anonymous):

@dean2291, here's A as an example, you can do the rest. A (8,12). x=8, y=12. 12 >= 8 + 3 (True) 12 < 2*8 (True) 8 > 6 (True) A is a solution.

OpenStudy (mathmale):

A would be a solution because it "satisfies" all 3 of the given conditions. Check out the other five points in the same manner.

OpenStudy (dean2291):

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