Question

Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0, -4).

Answer 1

Standard form is:
\(ax^2 + bx + c\)

What I like to do is put this in vertex form
\(a(x - h) + k\)

Answer 2

Sorry Vertex Form is \(a(x - h)^2 + k\)

Answer 3

Answer choices:
y = -1/4x^2
y^2 = -4x
y^2 = -16x
y = -1/16x^2

Answer 4

@Nnesha

Answer 5

My online lessons do such a poor job at explaining most things...

Answer 6

ok... so a vertex form for the parabola is

(x - h)^ = 4a(y - k) (h, k) is the vertex and a is the focal length

you know the vertex is (0,0) so you have

x^2 = 4ay

substitute the focal length to get the equation

so the answer would be.....1/36x^2=y

Answer 7

You just copy and pasted that from a yahoo answers page.

Answer 8

I would so laugh at you right now... No i didn't copy it from Yahoo, Yahoo is pointless to go to bc everything is always wrong

Answer 9

or another person's openstudy question because I was going through some pages and saw that word for word.

Answer 10

@Nnesha Please help

Answer 11

alright
so the equation is \[\large\rm (x-h)^2=4p(y-k)\]
where (h,k) is the vertex and p is the distance between vertex and focus

Answer 12

vertex is at origin so
origin =(0,0)

Answer 13

okay so h=0
k=0

Answer 14

that's correct

Answer 15

Which would then mean... (x-0)^2 = 4p(y-0)
x^2=4p(y)

Answer 16

now i'm going to draw a focus point
the focus point is below the vertex point so it should open downwards