Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (kkutie7):

quickish question about modeling differential equations

OpenStudy (kkutie7):

According to a simple physiological model, an athletic adult needs 20 calories per day per pound of body weight to maintain his weight. If he consumes more or fewer calories than those required to maintain his weight, his weight changes at a rate proportional to the difference between the number of calories consumed and the number needed to maintain his current weight. The constant of proportionality is 1/3500 pounds per calorie.

OpenStudy (kkutie7):

so \[\frac{dW}{dt}=some..constant(difference..in..calories)\] Suppose a person has a constant caloric intake of 2700 calories per day. Write a differential equation for W(t). Use upper case W.

OpenStudy (kkutie7):

i'm stuck on how to think about this

zepdrix (zepdrix):

If the person's weight is W, in pounds, Then to maintain body weight W, he must consume 20W calories per day. If he does not, then the rate of change of his weight, W', will be,\[\large\rm W'=C-20W\]Where C is amount of calories the person is taking in daily. I'm not sure how the constant of proportionality fits into this.. hmm Do they mean like this?\[\large\rm W'=k(C-20W)\]Hmmm I dunno :[

OpenStudy (kkutie7):

yes? I honestly don't know. C=2700

OpenStudy (kkutie7):

doesn't work.

jimthompson5910 (jim_thompson5910):

W(t) = person's weight in lbs at time t (20 calories/1 pound)*(W(t) pounds) = 20*W(t) calories to maintain the weight, the person must consume 20*W(t) calories it says that the person actually takes in 2700 calories per day difference = (actual intake) - (needed intake) difference = (2700) - (20W) difference = 2700 - 20W so I'm thinking it should be dW/dt = k*(2700 - 20W)

jimthompson5910 (jim_thompson5910):

`The constant of proportionality is 1/3500 pounds per calorie` so it looks like k = 1/3500

OpenStudy (kkutie7):

ok that make sense

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!