Question

check my answers?

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Answer 1

@hartnn

Answer 2

question 11: A = 30000 is correct,
both the others are incorrect.

Answer 3

how do you find extraneous solutions?

Answer 4

would the answer to the first question be -4?

Answer 5

@hartnn

Answer 6

@Rushwr

Answer 7

sorry for late reply

for 1st,
square both sides

x+4 = (x-2)^2


can you solve the quadratic to get 2 vales of x??
one of them is extraneous

Answer 8

i got x=(5,0)

Answer 9

plug 5 and 0 in the original equation and see what happens.
remember radical will give you only positive solution.

Answer 10

for example lets see 5
\[\Large \sqrt{5+4}=5-2\]
\[\Large \sqrt{9}=3\]
\[\Large 3=3\]
now try zero.

Answer 11

@kittymeow101 there?
put 0 in the original equation and see if both sides of '=' are same or not. if both sides are equal then 0 is not an extraneous root.

Answer 12

ok

Answer 13

there is no solution

Answer 14

@sami-21

Answer 15

so 0 is the extraneous root then.

Answer 16

ok ty, so could you help with no.12?

Answer 17

@sami-21

Answer 18

would the answer be option B

Answer 19

yes :)