A piece of ice of mass 40 g is dropped into 20 g of water at 50 Kelvin.Calculate the final temperature of water after all the ice has melted.
Sp heat capacity of water = 4200 J kg K
And L of ice = 336000 J kg^-1

Question

A piece of ice of mass 40 g is dropped into 20 g of water at 50 Kelvin.Calculate the final temperature of water after all the ice has melted.
Sp heat capacity of water = 4200 J kg K
And L of ice = 336000 J kg^-1

anonymous · Answer

@imqwerty

michele_laino · Answer

here the melting of the sample of ice occurs, furthermore, the water so produced is heated at the final temperature $t_e$. So we can write the subsequent equation of energy balance:
$$\Large  L{m_1} + {c_1}{m_1}\left( {{t_e} - {t_0}} \right) = {c_w}{m_2}\left( {{t_2} - {t_e}} \right)$$
where $m_1$ is the mass of sample of ice, $t_0=0°C=273.15K$, $t_2=50K$, $c_w$=specific heat of water, $m_2$ is the mass of water at $50K$

michele_laino · Answer

and $c_1$ is the specific heat of ice

anonymous · Answer

Is the final ans 8.75