Question

ALG2

Answer 1

Suppose a parabola has an axis of symmetry at x = -8, a maximum height of 2 and also passes through the point (-7, 1). Write the equation of the parabola in vertex form.

Answer 2

a.y=-7(x=2)^2 -8
b. y=-0.01(x-8)^2+2

Answer 3

c. y=-3(x+8)^2+2
d. y=-1.5(x-8)^2+2

Answer 4

the vertex point (x,y) lies on the axis of symmetry, and is either a maximum or a minimum y value depending on the direction the thing opens

Answer 5

where are you stuck at, or what do you know so far

Answer 6

what do i do first?

Answer 7

what is the vertex form for a parabola ?

Answer 8

standard form
\[\huge y=ax^2+bx+c\]

re-arranged to vertex form
\[\huge y=a*(x - h)^2 + k\]

Answer 9

the vertex is at the point (h,k) , lies on the axis of symmetry, and has a max/min y value

Answer 10

that is from, the axis of symmetry is at x=-8, the max height is y=2

so the thing must open downwards if the maximum is y=2, there you have your vertex point

Answer 11

y=a∗(x−h)2+k so now just plug in and solve?