can someone please come up with a radical equation and check for an extraneous solution?(its not supposed to be extraneous)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (phi):
set a square root equal to a positive number.
OpenStudy (anonymous):
so like 2√(5)
OpenStudy (anonymous):
@phi
OpenStudy (phi):
you want an equation. that means
left side = right side
you also want a variable (call it x)
the idea is to write
square root ( some expression with x) = some positive number
OpenStudy (anonymous):
oh and it has to model ax+b+c=d.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so 2√(5+4)+2=4
OpenStudy (anonymous):
so 2√(5+4)+2=4
OpenStudy (anonymous):
@phi
OpenStudy (anonymous):
2√(5+4)+2=4
-2 -2
2 √(5+4)=4
OpenStudy (anonymous):
2* sqrt 9=6
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
x=6?
OpenStudy (phi):
change it to this
\[ 2\sqrt{(x+4)}+2=4\]
because you need an x
OpenStudy (anonymous):
oh right
OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
ill solve it
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (phi):
now subtract 2 from both sides
what do you get ?
OpenStudy (anonymous):
2√(x+4)=2
OpenStudy (anonymous):
do i have to multiply both sides by 2?
OpenStudy (anonymous):
@phi
OpenStudy (phi):
you want to "get rid" of the 2 in front of the square root
notice you have 2 times square root
to get rid of the 2, do the opposite of multiply (to both sides)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ah
OpenStudy (phi):
in other words, divide both sides by 2
what do you get ?
OpenStudy (anonymous):
√4=1
OpenStudy (anonymous):
√x=4=1
OpenStudy (anonymous):
√x+4=1
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (phi):
almost, you mean
\[ \sqrt{x+4 }=1\]
OpenStudy (phi):
now square both sides
OpenStudy (anonymous):
x+16=1?
OpenStudy (phi):
if you have
\[ \sqrt{stuff}\]
and you square it, you get back stuff
you don't change what's inside ....
in other words, the only thing that changes is the square root "goes away"
OpenStudy (anonymous):
x+4=1?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (phi):
yes
OpenStudy (anonymous):
-4 to both side
OpenStudy (phi):
last step is add -4 to both sides
OpenStudy (anonymous):
x=-3
OpenStudy (anonymous):
add 4?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (phi):
yes. and if you put x=-3 into the equation
\[ 2 \sqrt{x+4}= 2 \]
the left side will simplify to 2, show x=-3 is not extraneous
OpenStudy (anonymous):
2√(-3+4)+2=2
2√(-3+4)=0
OpenStudy (anonymous):
idk the next step
OpenStudy (anonymous):
oh nvm
OpenStudy (anonymous):
2√1=0
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (phi):
I put in the wrong original equation
you started with
\[ 2\sqrt{(x+4)}+2=4 \]
to show x=-3 "works" , replace x with -3, and simplify only the left side (leave the = 4 alone)
OpenStudy (anonymous):
2√(-3+4)+2
2√(1)+2
OpenStudy (phi):
yes, and order of operations says now do sqrt(1)
OpenStudy (anonymous):
2
OpenStudy (phi):
sqrt(1) means what times itself = 1
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
oh
OpenStudy (phi):
sqrt(1)= 1 (notice 1 is special)
another example: sqrt(4) = 2 (because 2*2 is 4)
OpenStudy (phi):
sqrt(1) is 1 because 1*1 is 1
OpenStudy (anonymous):
i see
OpenStudy (phi):
2√(1)+2
becomes
2*1 + 2
now order of operations: do the multiply next
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
2*1=1
OpenStudy (anonymous):
2
OpenStudy (anonymous):
I'm sorry 2*1 is 2
OpenStudy (anonymous):
+2=4
OpenStudy (anonymous):
nooooo
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i mean yes
OpenStudy (anonymous):
its not extraneous
OpenStudy (anonymous):
thank you so much sir
OpenStudy (phi):
yes, that is good
you just showed
\[ 2\sqrt{(x+4)}+2=4 \]
becomes
4=4
when x= -3
so x=-3 makes the equation true (left side equals right side)
OpenStudy (anonymous):
Thank you, i just fanned u and gave you a medal and a testimonial
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ive lerned more now than the past 2 months in algebra