Question

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Answer 1

increasing at 1/4 units/sec

Answer 2

nope...its slightly more complicated...u need to differentiate with respect to t instead:

y=4x^2+1
dy/dt = d(4x^2+1)/dt

complete the diff above n use the given dx/dt=2 to find dy/dt. good luck :)

Answer 3

so I got increasing 16

Answer 4

yes, that is correct.

\[y = 4x^2+1\]\[\frac{dy}{dx} = 2*4x^{2-1}+2*0 = 8x^1=8x\]\[\frac{dx}{dt} = 2\]\[\frac{dy}{dt} = \frac{dy}{dx}*\frac{dx}{dt} = 8x*2=16x\]which evaluated at \(x=1\) gives \(16\)

Answer 5

thank you!!