(x-2)^2=100 Solve the quadratic function with square roots
It's already nicely set up for you. Find the two square roots and you're gold.
would the answer be 12?
That's one. Where did the other one go? It helps to write out your process, not just your answer.
theres another one?
Two. Hint: (2)^2 = 4 (-2)^2 = 4
if \[x^2=a \Longrightarrow |x|=\sqrt{a}\]
\[\large \sqrt{u^2}=\left| u \right|\]
even power
the reasoning is given by @tkhunny when you square positive and number like (-2)^2 (2)^2 the result is the same 4
that is why we are using absolute value
If I squared (x-2) all together and 100, I would get x-2=10 correct?
Well, after all that, did you find the second one? Here's how you find the first one: (x-2)^2 = 100 Square Root x-2 = 10 ==> x = 12 What you did not do was this: Square Root x-2 = -10 ==> What?
yes, if you square root something that is squared like root of (x-2)^2, that something can be positive or negative, \[\sqrt{(x-2)^2} = \left| x-2 \right| = 10\]
solving absolute value probs, that x-2 can be +10 or -10 2 values for x as @tkhunny showed above
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