Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

A climber is on a hike. After 2 hours she is at an altitude of 400ft. After 6 hours she is at an altitude of 700ft. What is her average rate of change? (I feel like this is a lot easier than I think but idk)

OpenStudy (texaschic101):

would it make it any easier if you knew the average rate of change is also the slope

OpenStudy (mathmale):

The "average rate of change" formula needed here is the same as that used for finding the slope of a straight line. You are given two points on the graph of a straight line: (2,400) and (6,700).

OpenStudy (anonymous):

Yes! thanks, but I'm blanking on how to set up the equation... from there I could solve

OpenStudy (texaschic101):

slope = (y2 - y1) / (x2 - x1)

OpenStudy (mathmale):

Find the slope of the line connecting these two points. That will also be your "average rate of change." Think back: What is the formula for the slope of a straight line when 2 points are given?

OpenStudy (mathmale):

I'd use slightly fancier graphics, but the concept presented by texaschic is correct.

OpenStudy (anonymous):

Would it be 4/2? (2)

OpenStudy (mathmale):

\[m=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\]

OpenStudy (anonymous):

|dw:1449208699265:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!