Complete the table given that h(x) = f(g(x))
x f(x) g(x) h(x)
0 1 2 3
1 9 0 1
2 ? 1 9
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OpenStudy (danjs):
the missing value will be f(2)
that value is on the table somewhere already
OpenStudy (anonymous):
so would it be 0?
OpenStudy (danjs):
h(x) = f [ g(x) ]
compound function, x--->g(x)--->f(x) ------>h(x)
starting with a value for x
you can get g(x), then f(x) is evaluated at that value for g(x)
do you understand the nested function thing?
OpenStudy (anonymous):
yes
OpenStudy (danjs):
look at row 2
x=1, g(1) = 0, f(g(1)) = f(0) = 1 [from row 1 when x=0]
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OpenStudy (danjs):
notice that matches h(1)
OpenStudy (danjs):
to figure f(x) when x is 2
need to find where g(x) = 2, and use that value in f(x)
OpenStudy (danjs):
g(x) = 2 when x=0
OpenStudy (anonymous):
yea so do you plug in 0 in f(x) now?
OpenStudy (danjs):
f(0) is 1,
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OpenStudy (anonymous):
huh ok that makes some sense now thank you!
OpenStudy (danjs):
h(2) = 9
f [ g(2)] = f [ 1] = 9
OpenStudy (anonymous):
im sorry, but im lost again, how does finding that help get f(2)?
OpenStudy (danjs):
k...
th emissing value is f(x) at x=2
OpenStudy (danjs):
but f(x) is defined in terms of g(x)
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OpenStudy (danjs):
so to get f(2), you need g(x) = 2
OpenStudy (anonymous):
which is 0?
OpenStudy (anonymous):
and then what would you do?
OpenStudy (danjs):
i need sleep.. lol here
OpenStudy (anonymous):
ahhh np man go ahead
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OpenStudy (danjs):
need f(x) = f(2), x=2
OpenStudy (danjs):
f[ g[x]]
start with x=2
g(2) = 1
f[g(2)] = f[1] = 9
so f(2) = 9
OpenStudy (danjs):
which should be h(2), good both are 9
OpenStudy (anonymous):
well alright then, thank you and have a good night!
OpenStudy (danjs):
welcome, sorry took so long
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