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Mathematics 17 Online
OpenStudy (anonymous):

Complete the table given that h(x) = f(g(x)) x f(x) g(x) h(x) 0 1 2 3 1 9 0 1 2 ? 1 9

OpenStudy (danjs):

the missing value will be f(2) that value is on the table somewhere already

OpenStudy (anonymous):

so would it be 0?

OpenStudy (danjs):

h(x) = f [ g(x) ] compound function, x--->g(x)--->f(x) ------>h(x) starting with a value for x you can get g(x), then f(x) is evaluated at that value for g(x) do you understand the nested function thing?

OpenStudy (anonymous):

yes

OpenStudy (danjs):

look at row 2 x=1, g(1) = 0, f(g(1)) = f(0) = 1 [from row 1 when x=0]

OpenStudy (danjs):

notice that matches h(1)

OpenStudy (danjs):

to figure f(x) when x is 2 need to find where g(x) = 2, and use that value in f(x)

OpenStudy (danjs):

g(x) = 2 when x=0

OpenStudy (anonymous):

yea so do you plug in 0 in f(x) now?

OpenStudy (danjs):

f(0) is 1,

OpenStudy (anonymous):

huh ok that makes some sense now thank you!

OpenStudy (danjs):

h(2) = 9 f [ g(2)] = f [ 1] = 9

OpenStudy (anonymous):

im sorry, but im lost again, how does finding that help get f(2)?

OpenStudy (danjs):

k... th emissing value is f(x) at x=2

OpenStudy (danjs):

but f(x) is defined in terms of g(x)

OpenStudy (danjs):

so to get f(2), you need g(x) = 2

OpenStudy (anonymous):

which is 0?

OpenStudy (anonymous):

and then what would you do?

OpenStudy (danjs):

i need sleep.. lol here

OpenStudy (anonymous):

ahhh np man go ahead

OpenStudy (danjs):

need f(x) = f(2), x=2

OpenStudy (danjs):

f[ g[x]] start with x=2 g(2) = 1 f[g(2)] = f[1] = 9 so f(2) = 9

OpenStudy (danjs):

which should be h(2), good both are 9

OpenStudy (anonymous):

well alright then, thank you and have a good night!

OpenStudy (danjs):

welcome, sorry took so long

OpenStudy (danjs):

want f when x=2 figure h(2) = 1 h(x) = 1 when x=2

OpenStudy (danjs):

so f(g(2)) = f(1) f(1) = 9 when x=1

OpenStudy (danjs):

so f(2) = 9

OpenStudy (anonymous):

alright thanks!

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