Question

Please help Algebra 2

Answer 1

Perform the indicated operation.

Answer 2

https://alphaomegaca.ignitiaschools.com/media/g_alg02_2015/5/184.gif

Answer 3

Flip the 2nd fraction and multiply

Answer 4

@iGreen

Answer 5

\[\frac{ (a+3)^2 }{ a-3 }\times \frac{ a^2-9 }{5 }\]

Answer 6

Correct, and can you multiply those 2 together?

Answer 7

Multiply the numerators together and multiply the denominators together.

Answer 8

im not sure how

Answer 9

i know it starts off \[2a^2\]

Answer 10

Okay, for the numerator we have \(\sf (a + 3)(a + 3)(a^2 - 9)\)

Answer 11

Can you multiply \(\sf (a + 3)(a + 3)\)?

Answer 12

a+9

Answer 13

No..

\(\sf a \times a\)
\(\sf a \times 3\)
\(\sf 3 \times a\)
\(\sf 3 \times 3\)

Multiply those

Answer 14

im confused

Answer 15

\(\sf a \times a \rightarrow a^2\)
\(\sf a \times 3 \rightarrow 3a\)
\(\sf 3 \times a \rightarrow 3a\)
\(\sf 3 \times 3 \rightarrow 9\)

Answer 16

Which gives us \(\sf a^2 + 6a + 9\), now multiply that to \(\sf a^2 - 9\)

Answer 17

ok i thought tht was it but i wasnt sure

Answer 18

so would this be a^4

Answer 19

or 6a^5

Answer 20

You gotta multiply all of them

Answer 21

\(\sf a^2 \times a^2\)
\(\sf a^2 \times -9\)
\(\sf 6a \times a^2\)
\(\sf 6a \times -9\)
\(\sf 9 \times a^2\)
\(\sf 9 \times -9\)

Answer 22

The first one equals \(\sf a^4\), that's correct.

Answer 23

the 2nd 1 is a^2-9

Answer 24

No, it's \(\sf -9a^2\)

Answer 25

oh ok

Answer 26

3=6a^3

Answer 27

Correct.

Answer 28

would 4 be -54a

Answer 29

5 wouldbt 9a^2 and 6 would be -81

Answer 30

4 is correct.

Answer 31

So are 5 and 6.

Answer 32

ok

Answer 33

That gives us:

\(\sf a^4 - 9a^2 + 6a^3 - 54a + 9a^2 - 81\)

Answer 34

Combine like terms and you got:

\(\sf a^4 + 6a^3 - 54a - 81\)

Answer 35

Now simplify the denominator. \(\sf 5(a - 3)\)

Answer 36

5a-3

Answer 37

Multiply 5 to both terms.

Answer 38

\(\sf 5 \times a\)
\(\sf 5 \times -3\)

Answer 39

5a and -15

Answer 40

Yes, that gives us:

\(\sf\dfrac{ a^4 + 6a^3 - 54a - 81}{5a - 15}

Answer 41

i cant read it @green_1

Answer 42

@iGreen

Answer 43

sorry @green_1 i meant to tag someone else

Answer 44

you mean the equation above

Answer 45

the last thing posted i cant read it

Answer 46

@iGreen could u repost the last thing