Question

solve for x: 5/x^2-4+2/x=2/x-2

Answer 1

https://cdn.flvsgl.com/assessment_images/algebra2_v13_2_gs_xml/72050_53b5a99e/07_08c_3_02.gif

Answer 2

Okay, we can't see that file.

Does the problem look like this?

\[\frac{ 5}{x^2-4}+\frac{2}{x}=\frac{2}{x-2}\]If so, when you type it all on a single line, you need to put parentheses around the numerators and denominators:
5/(x^2-4) + 2/x = 2/(x-2)

By the order of operator precedence, what you wrote actually means
\[ \frac{5}{x^2}-4+\frac{2}{x}=\frac{2}{x}-2\]which is entirely different, I hope you'll agree!

Answer 3

@whpalmer4 it's the first way you typed it.

Answer 4

@whpalmer4 yes it's the first one

Answer 5

is it 8?

Answer 6

nvm!!! im right!!

Answer 7

Let's check it and find out!

\[\frac{ 5}{x^2-4}+\frac{2}{x}=\frac{2}{x-2}\]substitute \(x = 8\)
\[\frac{ 5}{8^2-4}+\frac{2}{8}=\frac{2}{8-2}\]\[\frac{5}{60}+\frac{2}{8}=\frac{2}{6}\]Looks like 240 is a common denominator\[\frac{4}{4}*\frac{5}{60}+\frac{30}{30}*\frac{2}{8} = \frac{40}{40}*\frac{2}6\]\[\frac{20+60}{240}=\frac{80}{240}\checkmark\]Yes, \(x=8\) is the solution